Consider a U-tube manometer whose arms are open to the atmosphere as shown in theschematic. There are two manometer fluids: oil with density of poil = 900 kg/m' and anunspecified fluid with density of Pu = 1500 kg/m³. For the fluid heights in the manometershown in the schematic, determine the height, h, of the unspecified fluid in the rightmanometer arm.openopenoilunspecifiedfluid15cmh = ?20cm

The pressure head in the manometer is calculated by using the equation, P=ρgh.

Answered: Consider a U-tube manometer whose arms…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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2. The U-tube manometer shown contains multiple fluids. For the given heights of the fluids, calculate the pressure in "A", in kPa. * oil (sg = 0.9) oil (sg = 0.8) 1.50 m 0.90 m water 0.30 m mercury (sg = 13.6) to 0.30 m
Can someone please explain the parts marked on the photo. Like why is there no two included in the other equation and the steps taken to find Poisson equation. Please actually show step by step including the calculations to find the final answer. Thanks
A fluid of specific gravity 0.8 is flowing in a pipe. The pressure drop across a flow secti between 1 and 2 is measured by a differential manometer as shown in the figure below The manometric fluid is mercury (S = 13.6). The pressure drop is Fluid (5-0.8) 2 m 0.5 m He Assume density of water is 1000 kg/m³ and g = 9.81 m/s².
Q03
The Venturi meter shown in the sketch below, contracts the flow down to one quarter of its original area. Cold air at 0 deg C flows in the pipe through the Venturi meter. The velocity of the air upstream of the Venturi meter is equal to 40 ft/s and the pressure at the same point is equal to 30 psia. What is the manometer reading if the fluid of the manometer is water with density 1000 kg/m3 . Assume that the air behaves as an ideal gas with molecular weight equal to Mw=29 kg/kmol and constant density evaluated at upstream conditions. Use Bernoulli's equation for your calculations. please respond asap!
(Bernoulli/continuity/Pitot tube) Two Pitot tubes and two static pressure taps are placed in the pipe contraction shown in the figure below. The flowing fluid is water, and viscous effects are negligible. Determine the two manometer readings, h and H. V=1.7 ft/s h = H= 6.4 in. Air ↓ SG= 1.10 ft ft TH 3.8 in.
In the figure shown, the distance y + 1/2 z = 1.20 m. When fluid A is water, fluid B is mercury, and the pressure at "m" is vacuum of 37 kPa, compute "z". FLUID A y FLUID B MERCURY a. -0.380 m O b. -0.407 m c. 0.174 m d. 0.196 m
1) A manometer is attached to two pipes as shown. If knowing mercury SG is 13.6, sea water SG is 1.035, and fresh water p is 1,000 kg/m³, determine the pressure difference between two pipelines at the centers. Fresh Water h. -60 cm Air hair -70 cm hea <- 40 cm Mercury Sea Water hi -10 cm
The inclined-tube manometer shown in the figure below is used to measure small pressure changes. Determine the difference in pressure between points A and E if the manometer liquid, mercury, is in the position shown. The pipe at A contains water and the one at E contains natural gas. For mercury, YHg = 846 Ib/ft³. E 8 in. 120 14 in. 2 in

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