Circuit analysis using phasor/impedance, complex power calculation: A three-phase RLC circuit is shown below. The reactance of the capacitor is 40 Ohm. The reactance of the inductor is 80 Ohm, and the resistor is 8 Ohm. The sending end voltage is v₁(t) = √2³45 cos(wt + 7) kV, where w = 2π-60 rad/s. The receiving end voltage is v2(t) = √2³45 cos(wt) kV. The power base is 1000 MVA and the voltage base (L-L) is 345 kV. . Please compute total transferred complex power and S₂ in the physical unit. • Please draw a per-phase phasor/impedance diagram using per unit values. • Please compute the per unit complex power S₁ and S₂. RL C mm F Figure ->> Vr

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Circuit analysis using phasor/impedance, complex power calculation: A three-phase RLC circuit
is shown below. The reactance of the capacitor is 40 Ohm. The reactance of the inductor is 80 Ohm, and the
resistor is 8 Ohm. The sending end voltage is v₁ (t) = √2³45 cos(wt + 7) kV, where w = 2 · 60 rad/s. The
receiving end voltage is v2(t) = √√2³45 cos(wt) kV. The power base is 1000 MVA and the voltage base (L-L) is
345 kV.
• Please compute total transferred complex power S₁ and S₂ in the physical unit.
• Please draw a per-phase phasor/impedance diagram using per unit values.
• Please compute the per unit complex power S₁ and S₂.
Si
→>>>
777
RL C
mmmll
Figure
Vr
Transcribed Image Text:Circuit analysis using phasor/impedance, complex power calculation: A three-phase RLC circuit is shown below. The reactance of the capacitor is 40 Ohm. The reactance of the inductor is 80 Ohm, and the resistor is 8 Ohm. The sending end voltage is v₁ (t) = √2³45 cos(wt + 7) kV, where w = 2 · 60 rad/s. The receiving end voltage is v2(t) = √√2³45 cos(wt) kV. The power base is 1000 MVA and the voltage base (L-L) is 345 kV. • Please compute total transferred complex power S₁ and S₂ in the physical unit. • Please draw a per-phase phasor/impedance diagram using per unit values. • Please compute the per unit complex power S₁ and S₂. Si →>>> 777 RL C mmmll Figure Vr
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