Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Draw the major organic product of the following Friedel–Crafts alkylation. (An excess of benzene is present.) Do not draw any aluminum byproducts.
Transcribed Image Text:This image depicts a chemical reaction involving the alkylation of benzene, which is a Friedel-Crafts alkylation reaction.
**Reaction Components:**
- **Benzene (C₆H₆):** Represented by the hexagon with alternating double bonds, indicating the aromatic ring. It is mentioned in excess, suggesting that benzene is used in a larger quantity to drive the reaction towards the desired product.
- **2-Chloropropane:** This is the alkylating agent. It is represented as a three-carbon chain with a chlorine atom attached to the middle carbon atom.
- **AlCl₃ (Aluminum Chloride):** Acts as a catalyst in this reaction. It helps in generating a more electrophilic species from the alkyl chloride to facilitate the reaction with the benzene ring.
**Reaction Arrow:**
- The arrow to the right signifies the direction of the reaction, from reactants (left) to products (right), though the products are not shown in the diagram.
In this reaction, the benzene will react with 2-chloropropane in the presence of AlCl₃ to form isopropylbenzene (cumene). This is achieved through the electrophilic substitution mechanism facilitated by the Lewis acid catalyst AlCl₃.
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