USING THE ATTACHED TABLES, PLEASE SOLVE PART F.To test HO:u=100 versus H1: u not equal to 100, a simple random sample n=21 is obtained from a population that is known to be normally distributed.A. if xbar =104 and s=9.5 compute the test statistictest statistic is 1.925B. If the researcher decides to test this hypothesis at the a=.01 level of significance, determine the critical value.CV= -2.845, 2.845C and D were graphs and a statement.E. Construct a 99% confidence interval to test the hypothesis. The confidence interval is 98.1021, 109.8979.F. Choose do not reject or reject HO based on the confidence interval because the hypothesized value u=100 is or is not in the interval. df0.250.200.150.100,050.0250.020.010.0050.00250.0010.0005df11.0001.3761.9633.0786.31412.70615.89431.82163.657127.321318.309636.619131.59912.9248.6100.8161.0611.3861.8862.9204.3034.8496.9659.92514.08922.3271.6381.5335.8414.60430.7650.7410.9781.2501.1902.3532.1323.1822.7763.4822.9994.5413.7477.4535.59810.21530.9417.1735.8930.7270.9201.1561.4762.01525712.7573.3654.0324.7736.86951.1341.1190.7180.9061.4405.9591.9431.8951.8602.4472.6123.1433.7074.3175.2086.3.4993.35570.7110.7060.8960.8891.4151.3972.3652.3062.5172.4492.9982.8964.0293.8334.7854.5015.4085.04171.1081.1000.8831.3831.3720.7031.8332.2622.3982.8213.2503.6904.2974.781100.7000.8791.0931.8122.2282.3592.7643.1693.5814.1444.587103.1063.0553.0123.4973.4284.0253.9303.852110.6970.8761.0881.3631.7962.2012.3282.7182.6812.6504.437110.8730.8702.1792.1602.1452.13112130.6950.6941.0831.0791.0761.3561.3501.3451.7821.7712.3034.3184.22112130.6920.6911.7611.7532.2822.2642.2493.3723.326140.8682.6242.9772.9473.7874.14014150.8661.0741.3412.6023.2863.7334.0731516170.6900.6890.8650.8631.0711.0691.3371.3331.3302.5832.5671.7462.1202.1102.2352.2242.9212.8983.2523.6863.6464.01516171.7403.2223.1973.965180.6880.8621.0671.7342.1012.2142.5522.5392.8783.6103.922183.5793.5523.8833.850190.6880.8611.0661.3281.7292.0932.2052.8613.17419200.6870.8601.0641.3251.7252.0862.1972.5282.8453.15320 21220.6860.6860.8590.8581.0631.0611.3231.7211.7172.0802.0742.1892.1832.5182.8312.8193.1353.1193.5273.5053.8193.79221221.3212.5080.6851.7141.7111.708230.8581.0601.3192.0692.1772.1722.5002.8073.1043.4853.768233.4673.4501.05924251.3181.3162.4922.4850.6850.8572.0642.7973.0913.745240.6840.8561.0582.0602.1672.7873.0783.72525260.6840.8561.0581.3151.7063.0672.0562.0522.1622.4792.7793.4353.4213.707260.6840.6830.8550.855271.0571.3141.7032.1582.4732.7712.7633.0573.690271.7011.6991.6972.4672.4622.457281.0561.3132.0482.1543.0473.4083.6742829300.6830.6831.0551.0550.8541.3111.3102.0452.0422.1502.1472.7562.7503.0383.3963.6593.64629300.8543.0303.3850.6820.682310.8531.0541.3091.6962.0402.1442.4532.7443.0223.0153.3753.63331320.8531.0541.3091.6942.0372.1412.4492.7383.3653.3563.622323334350.6820.8531.0531.3081.6922.0352.1382.4452.7333.0083.6113.6013.591330.8520.8521.6911.6902.0322.0300.6821.0521.0521.3072.1362.1332.4412.4382.7282.7243.0023.34834350.6821.3062.9963.340360.6810.8521.0521.3061.6882.0282.1312.4342.7192.9903.3333.582362.7152.7122.708370.6810.8511.0511.3051.6872.0262.1292.4312.9853.3263.5743738390.6810.6810.8510.8511.0511.0501.3041.6861.6852.0242.0232.1272.1252.4292.4262.9802.9763.3193.3133.5663.55838391.304400.6810.8511.0501.3031.6842.0212.1232.4232.7042.9713.3073.55140500.6790.8491.0471.2991.6762.0092.1092.4032.6782.9373.2613.4965006701 0451 2062 n002 2002 6602 0152 A601671

It is given that Confidence interval = (98.1021, 109.8979) Hypotheses : H0 : μ = 100 versus H1: μ ≠…

Answered: Choose do not reject or reject HO based…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

USING THE ATTACHED TABLES, PLEASE SOLVE PART F.

To test HO:u=100 versus H1: u not equal to 100, a simple random sample n=21 is obtained from a population that is known to be normally distributed.

A. if xbar =104 and s=9.5 compute the test statistic

test statistic is 1.925

B. If the researcher decides to test this hypothesis at the a=.01 level of significance, determine the critical value.

CV= -2.845, 2.845

C and D were graphs and a statement.

E. Construct a 99% confidence interval to test the hypothesis. The confidence interval is 98.1021, 109.8979.

F. Choose do not reject or reject HO based on the confidence interval because the hypothesized value u=100 is or is not in the interval.

df
0.25
0.20
0.15
0.10
0,05
0.025
0.02
0.01
0.005
0.0025
0.001
0.0005
df
1
1.000
1.376
1.963
3.078
6.314
12.706
15.894
31.821
63.657
127.321
318.309
636.619
1
31.599
12.924
8.610
0.816
1.061
1.386
1.886
2.920
4.303
4.849
6.965
9.925
14.089
22.327
1.638
1.533
5.841
4.604
3
0.765
0.741
0.978
1.250
1.190
2.353
2.132
3.182
2.776
3.482
2.999
4.541
3.747
7.453
5.598
10.215
3
0.941
7.173
5.893
0.727
0.920
1.156
1.476
2.015
2571
2.757
3.365
4.032
4.773
6.869
5
1.134
1.119
0.718
0.906
1.440
5.959
1.943
1.895
1.860
2.447
2.612
3.143
3.707
4.317
5.208
6.
3.499
3.355
7
0.711
0.706
0.896
0.889
1.415
1.397
2.365
2.306
2.517
2.449
2.998
2.896
4.029
3.833
4.785
4.501
5.408
5.041
7
1.108
1.100
0.883
1.383
1.372
0.703
1.833
2.262
2.398
2.821
3.250
3.690
4.297
4.781
10
0.700
0.879
1.093
1.812
2.228
2.359
2.764
3.169
3.581
4.144
4.587
10
3.106
3.055
3.012
3.497
3.428
4.025
3.930
3.852
11
0.697
0.876
1.088
1.363
1.796
2.201
2.328
2.718
2.681
2.650
4.437
11
0.873
0.870
2.179
2.160
2.145
2.131
12
13
0.695
0.694
1.083
1.079
1.076
1.356
1.350
1.345
1.782
1.771
2.303
4.318
4.221
12
13
0.692
0.691
1.761
1.753
2.282
2.264
2.249
3.372
3.326
14
0.868
2.624
2.977
2.947
3.787
4.140
14
15
0.866
1.074
1.341
2.602
3.286
3.733
4.073
15
16
17
0.690
0.689
0.865
0.863
1.071
1.069
1.337
1.333
1.330
2.583
2.567
1.746
2.120
2.110
2.235
2.224
2.921
2.898
3.252
3.686
3.646
4.015
16
17
1.740
3.222
3.197
3.965
18
0.688
0.862
1.067
1.734
2.101
2.214
2.552
2.539
2.878
3.610
3.922
18
3.579
3.552
3.883
3.850
19
0.688
0.861
1.066
1.328
1.729
2.093
2.205
2.861
3.174
19
20
0.687
0.860
1.064
1.325
1.725
2.086
2.197
2.528
2.845
3.153
20

21
22
0.686
0.686
0.859
0.858
1.063
1.061
1.323
1.721
1.717
2.080
2.074
2.189
2.183
2.518
2.831
2.819
3.135
3.119
3.527
3.505
3.819
3.792
21
22
1.321
2.508
0.685
1.714
1.711
1.708
23
0.858
1.060
1.319
2.069
2.177
2.172
2.500
2.807
3.104
3.485
3.768
23
3.467
3.450
1.059
24
25
1.318
1.316
2.492
2.485
0.685
0.857
2.064
2.797
3.091
3.745
24
0.684
0.856
1.058
2.060
2.167
2.787
3.078
3.725
25
26
0.684
0.856
1.058
1.315
1.706
3.067
2.056
2.052
2.162
2.479
2.779
3.435
3.421
3.707
26
0.684
0.683
0.855
0.855
27
1.057
1.314
1.703
2.158
2.473
2.771
2.763
3.057
3.690
27
1.701
1.699
1.697
2.467
2.462
2.457
28
1.056
1.313
2.048
2.154
3.047
3.408
3.674
28
29
30
0.683
0.683
1.055
1.055
0.854
1.311
1.310
2.045
2.042
2.150
2.147
2.756
2.750
3.038
3.396
3.659
3.646
29
30
0.854
3.030
3.385
0.682
0.682
31
0.853
1.054
1.309
1.696
2.040
2.144
2.453
2.744
3.022
3.015
3.375
3.633
31
32
0.853
1.054
1.309
1.694
2.037
2.141
2.449
2.738
3.365
3.356
3.622
32
33
34
35
0.682
0.853
1.053
1.308
1.692
2.035
2.138
2.445
2.733
3.008
3.611
3.601
3.591
33
0.852
0.852
1.691
1.690
2.032
2.030
0.682
1.052
1.052
1.307
2.136
2.133
2.441
2.438
2.728
2.724
3.002
3.348
34
35
0.682
1.306
2.996
3.340
36
0.681
0.852
1.052
1.306
1.688
2.028
2.131
2.434
2.719
2.990
3.333
3.582
36
2.715
2.712
2.708
37
0.681
0.851
1.051
1.305
1.687
2.026
2.129
2.431
2.985
3.326
3.574
37
38
39
0.681
0.681
0.851
0.851
1.051
1.050
1.304
1.686
1.685
2.024
2.023
2.127
2.125
2.429
2.426
2.980
2.976
3.319
3.313
3.566
3.558
38
39
1.304
40
0.681
0.851
1.050
1.303
1.684
2.021
2.123
2.423
2.704
2.971
3.307
3.551
40
50
0.679
0.849
1.047
1.299
1.676
2.009
2.109
2.403
2.678
2.937
3.261
3.496
50
0670
1 045
1 206
2 n00
2 200
2 660
2 015
2 A60
1671

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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