Choose the array below which correctly represents the backing store for the following min heap.5526255762(679663O [0,14,26,25,96,67,63,55,57,62]O [0,14,26,96,67,25,63,55,57,62]O [96,26,67,14,63,25,0,null,57,null,55,62]]O [0,14,55,26,25,57,62,96,67,63]

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Choose the array below which correctly represents the backing store for the following min heap. 14 55 (26 (25 (57 (62 (96 (67 (63 O [0,14,26,25,96,67,63,55,57,62] O [0,14,26,96,67,25,63,55,57,62] O [96,26,67,14,63,25,0,null,57,null,55,62]] O [0,14,55,26,25,57,62,96,67,63]

Choose the array below which correctly represents the backing store for the following min heap. 14 55 (26 (25 (57 (62 (96 (67 (63 O [0,14,26,25,96,67,63,55,57,62] O [0,14,26,96,67,25,63,55,57,62] O [96,26,67,14,63,25,0,null,57,null,55,62]] O [0,14,55,26,25,57,62,96,67,63]

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def large_matrix(matrix: list[list[int]]) -> int:"""Returns the area of the rectangle in the area of a rectangle is defined by number of 1's that it contains.The matrix will only contain the integers 1 and 0.>>> case = [[1, 0, 1, 0, 0],... [1, 0, 1, 1, 1],... [1, 1, 1, 1, 1],... [1, 0, 0, 1, 0]]>>> largest_in_matrix(case1)6"" You must use this helper code: def large_position(matrix: list[list[int]], row: int, col: int) -> int: a = rowb = colmax = 0temp = 0rows = len(matrix)column = len(matrix[a])while a < rows and matrix[a][col] == 1:temp = 0while b < column and matrix[a][b] == 1:temp = temp + 1b = b + 1column = ba = a + 1if (a != row+1):temp2 = temp * (a - row)else:temp2 = tempif max < temp2:max = temp2b = colreturn max """ remember: Please do this on python you should not use any of the following: dictionaries or dictionary methods try-except break and continue statements recursion map / filter import""'
2.) C [10] = {5, 1,2,8,6,10,3,9,4,7} heap size = 10 Do Heapify (C, 1). What the values in the array C starting from the index 0 to 9?
Q2 You have a dynamic array with 3 elements in it and a capacity of 4. The capacity doubles when additional space is needed and shrinks by 50% (rounding down) when the size is at or below 1/3 capacity. Answer the questions below for the following operation sequence: Add, Add, Remove, Remove, Remove Q2.1 What will be the capacity of the list when the whole sequence is completed? Answer= Enter your answer here
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char ** doubleIt (char **arr, int *maxsize); The doubleIt function will increase the heap size by doubling the original space. The functions takes 2 arguments: 1. A double pointer of type char called arr. This is a 2D dynamic array that contains words (strings) from the respective category (noun, verb, adjective, preposition). This is the original heap. 2. A pointer of type int called maxsize. This pointer holds the address of an integer that keeps track of the maximum amount of strings the 2D dynamic array can store. When this function is invoked, the current size of the dynamic array is at capacity so the values should match. This value will need to be multiplied by 2. The function allocates a new heap that is twice the size of the original heap and copy the values from the original heap into the new heap. One important note about this is that you have to properly copy the values over in order to avoid segmentation fault. Think about how this can be avoided. That is part of the…