ASSUME S, T R are stacks. A is an array [1..14] of char; THE INPUT IS "datastructures". The MAXSTACK VALUES FOR R, S ARE 5 AND For T is 7. ALL THREE STACKS WILL CONTAIN CHARACTER DATA. ASSUME ch is a character variable. Also ASSUME that there is NO SPACE in the input. ClearStack (S);ClearStack (T); ClearStack(R ); FORI = 1 to 14 READ(A[1]); END FOR; I = 1; While I < 15 IF NOT FULLSTACK(R) PUSH(R, A[]) ELSE IF NOT FULLSTACK(S) PUSH(S, A[1]); ENDIF; IF (A[I ] = "u" OR A[] = "r") and (Not FullStack(T)) PUSH(T, A[]); ENDIF; I = 1 + 1; EndWhile; While Not EmptyStack (R) Pop (R, ch); Write (ch); If Not Fullstack(T) Push (T, ch); Endif: EndWhile; While Not EmptyStack(T) Pop (T, ch); Write (ch); EndWhile; output tracing
ASSUME S, T R are stacks. A is an array [1..14] of char; THE INPUT IS "datastructures". The MAXSTACK VALUES FOR R, S ARE 5 AND For T is 7. ALL THREE STACKS WILL CONTAIN CHARACTER DATA. ASSUME ch is a character variable. Also ASSUME that there is NO SPACE in the input. ClearStack (S);ClearStack (T); ClearStack(R ); FORI = 1 to 14 READ(A[1]); END FOR; I = 1; While I < 15 IF NOT FULLSTACK(R) PUSH(R, A[]) ELSE IF NOT FULLSTACK(S) PUSH(S, A[1]); ENDIF; IF (A[I ] = "u" OR A[] = "r") and (Not FullStack(T)) PUSH(T, A[]); ENDIF; I = 1 + 1; EndWhile; While Not EmptyStack (R) Pop (R, ch); Write (ch); If Not Fullstack(T) Push (T, ch); Endif: EndWhile; While Not EmptyStack(T) Pop (T, ch); Write (ch); EndWhile; output tracing
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![ASSUME S, T R are stacks. A is an array [1..14] of char; THE INPUT IS "datastructures". The MAXSTACK VALUES FOR R, S ARE 5 AND For T is 7. ALL THREE STACKS
WILL CONTAIN CHARACTER DATA. ASSUME ch is a character variable. Also ASSUME that there is NO SPACE in the input. ClearStack(S); ClearStack (T); ClearStack (R
); FOR I = 1 to 14 READ(A[1]); END FOR; I = 1; While I < 15 IF NOT FULLSTACK(R) PUSH(R, A[I]) ELSE IF NOT FULLSTACK(S) PUSH(S, A[I]); ENDIF; IF (A[I
"r") and (Not FullStack(T)) PUSH(T, A[1]); ENDIF; I = 1 + 1; EndWhile; While Not EmptyStack(R) Pop (R, ch); Write (ch); If Not Fullstack(T) Push
(T, ch); Endif: EndWhile; While Not EmptyStack (T) Pop(T, ch); Write (ch); EndWhile; output tracing
]
"u" OR A[!]
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4c40ff7-177f-488a-88c7-3a1dfd41b401%2F8029a6c8-6813-4164-9a0e-d7d7133dd7b4%2Fz0kgc6_processed.png&w=3840&q=75)
Transcribed Image Text:ASSUME S, T R are stacks. A is an array [1..14] of char; THE INPUT IS "datastructures". The MAXSTACK VALUES FOR R, S ARE 5 AND For T is 7. ALL THREE STACKS
WILL CONTAIN CHARACTER DATA. ASSUME ch is a character variable. Also ASSUME that there is NO SPACE in the input. ClearStack(S); ClearStack (T); ClearStack (R
); FOR I = 1 to 14 READ(A[1]); END FOR; I = 1; While I < 15 IF NOT FULLSTACK(R) PUSH(R, A[I]) ELSE IF NOT FULLSTACK(S) PUSH(S, A[I]); ENDIF; IF (A[I
"r") and (Not FullStack(T)) PUSH(T, A[1]); ENDIF; I = 1 + 1; EndWhile; While Not EmptyStack(R) Pop (R, ch); Write (ch); If Not Fullstack(T) Push
(T, ch); Endif: EndWhile; While Not EmptyStack (T) Pop(T, ch); Write (ch); EndWhile; output tracing
]
"u" OR A[!]
=
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