ching and lear X water treatment systems - Forkly X + /takeAssignment/takeCovalentActivity.do?locator=Dassignment-take [Review Topica) [References) Use the References to access important values if needed for this question. The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in chloroform is aspirin. Calculate the vapor pressure of the solution at 25 °C when 8.475 grams of aspirin, C,Hg0, (180.1 g/mol), are dissolved in 237.0 grams of chloroform. chloroform = CHCI3 = 119.40 g/mol. %3D VP(solution) |mm Hg Submit Answer Retry Entire Group 9 more group attempts remaining

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The problem displayed involves calculating the vapor pressure of a solution where aspirin is dissolved in chloroform. Here's the detailed transcription:

---

**Vapor Pressure of a Solution:**

The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in chloroform is aspirin.

Calculate the vapor pressure of the solution at 25 °C when 8.475 grams of aspirin (C₉H₈O₄, 180.1 g/mol) are dissolved in 237.0 grams of chloroform.

- **Chloroform** = CHCl₃ = 119.40 g/mol
- \[ \text{VP (solution)} = \_\_\_\_ \text{ mm Hg} \]

[Submit Answer] [Retry Entire Group]

9 more group attempts remaining

---

**Explanation:**

To solve this problem, you would typically use Raoult's Law, which relates the vapor pressure of a solution to the mole fraction of the solvent and the vapor pressure of the pure solvent. The key here is to calculate the mole fraction of chloroform in the solution. This requires determining the moles of both chloroform and aspirin.

There are no graphs or diagrams included in this image.
Transcribed Image Text:The problem displayed involves calculating the vapor pressure of a solution where aspirin is dissolved in chloroform. Here's the detailed transcription: --- **Vapor Pressure of a Solution:** The vapor pressure of chloroform is 173.11 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in chloroform is aspirin. Calculate the vapor pressure of the solution at 25 °C when 8.475 grams of aspirin (C₉H₈O₄, 180.1 g/mol) are dissolved in 237.0 grams of chloroform. - **Chloroform** = CHCl₃ = 119.40 g/mol - \[ \text{VP (solution)} = \_\_\_\_ \text{ mm Hg} \] [Submit Answer] [Retry Entire Group] 9 more group attempts remaining --- **Explanation:** To solve this problem, you would typically use Raoult's Law, which relates the vapor pressure of a solution to the mole fraction of the solvent and the vapor pressure of the pure solvent. The key here is to calculate the mole fraction of chloroform in the solution. This requires determining the moles of both chloroform and aspirin. There are no graphs or diagrams included in this image.
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