There are 20 commonly occurring amino acids from which all proteins are derived, although many other less common aminoacids have been isolated from natural sources. Valine is one of the 20 common amino acids, and it was used as a startingmaterial in the laboratory synthesis of an uncommon amino acid. During one of the steps in the synthesis, compound 1 wastreated with HBr under conditions that favor radical addition, giving stereoisomers 2 and 3.H.OCH3HBr2 + 3hv(S)-valineDraw the structures of 2 and 3.

Answered: There are 20 commonly occurring amino…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A mixture of 0.10 mol benzene and 0.10 mol 1,4-dimethyl benzene was allowed to react with 0.10 mol nitronium ion until all the nitronium ion was gone. Two products were formed: 0.002 mol of one and 0.098 mol of the other. Draw the structures of the major and minor products.
1. Guanine (1) is commonly represented as a non aromatic, partially saturated heterocycle. However, the common structure of guanine is only one of two possible resonance forms, of whom the second one is clearly aromatic. Knowing that the latter is originated by the delocalisation of one of N6 (nitrogen six) lone pair on the ring, would you be able to predict the structure of the aromatic resonance structure of guanine? Guanine 6 N. 'NH 3 R 1 Why cannot N4 delocalise its lone pair on the ring? What about N3? Is its lone pair delocalised on the pyrimido-imidazole ring? Why?
In addition to more highly fluorinated products, fluorination of 2-methylbutane yields a mixture of compounds with the formula C5H10F2. Draw the structures of all the isomers with the formula C5H10F2 that would be produced and label with a star all the chiral centers present in their structures.
A chemist synthesized compound X as a racemic mixture. When the ketone group in X was enzymatically reduced to the corresponding alcohol, a 100% yield was obtained of the product shown below. Choose the statement that best describes this result. ОН enzyme C;H1 `OCH,CH; pH 4.0 C3H1 `OCH,CH3 ОН ÕH X (racemic) (100% yield) One enantiomer of compound X reacts quickly with the enzyme. The other enantiomer of compound X is unreactive, but rapidly equilibrates with the reactive enantiomer under the reaction conditions. Since compound X was racemic, it makes sense that only a single product was obtained. O The product is a meso compound, so either enantiomer of compound X gives the same product. One enantiomer of compound X reacts quickly with the enzyme, while the other enantiomer of compound X remains unchanged.
Aspirin, or 2-acetoxybenzoic acid, (C9H8O4) is often synthesised from salicylic acid.(i) Sketch and discuss any changes in the number of possible structural conformations ofaspirin relative to those of salicylic acid. (ii) Re-draw the structure predicted to be the lowest energy conformation of aspirin,indicating any expected stabilising and destabilising interactions. Justify your choice.
One of the following statements is incorrect in using Simmons-Smith reagent to prepare cyclopropane: а. Zn(Cu) reacts with CH212 in ether to yield iodomethylzinc iodide, ICH2ZNI. b. ICH2ZNI reacts with an alkene in ether to form a O cyclopropane С. ICH21 is a "carbenoid" since it resembles carbene (:CH2) chemically. d. The reaction is not stereospecific
the compound B C23H46,a sex attractant of the common housefly,gave two products Ch3(cH2)12COOH and CH3(CH2)7COOH. Based on this information, suggest the likely structures of B
Compound X, C,4H12Br2, is optically inactive. On treatment with strong base, X gives hydrocarbon Y, C14H10: Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst to give z (C14H14) and reacts with ozone to give one product, benzoic acid (C,Hg02). Draw the structure of compound Z. • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • Ignore alkene stereochemistry. • If more than one structure fits the description, draw them all. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures with + signs from the drop-down menu. ChemDoodle
a) If the pH value of an aqueous solution of trimethylamine [(CH3) 3N] is 10.75, what should be the molarity of this solution? (CH3) 3N + H2O ↔ (CH3) 3NH + + OH-, Kb = 6.3 × 10-5 b) What will be the pH of the solution prepared by dissolving 8.35 g of aniline hydrochloride (C6H5NH3 + Cl-) in 750 mL of 0.215 M aniline (C6H5NH2)? Is this solution an effective buffer? Explain (Kb = 7.4 × 10-10 for aniline, C: 12.0 g / mol, H: 1.0 g / mol, N: 14.0 g / mol, Cl: 35.4 g / mol) .
A chiral amine A having the R conguration undergoes Hofmann elimination to form an alkene B as the major product. B is oxidatively cleaved with ozone, followed by CH3SCH3, to form CH2 = O and CH3CH2CH2CHO. What are the structures of A and B?
Complete the statement, "Cyclooctadeca-1,3,5,7,9,11,13,15,17-nonaene [C18H18] is antiaromatic; reacts with Bromine antiaromatic; has 4n pi electrons aromatic; has 4n+2 pi electrons nonaromatic;is nonplanar nonaromatic; more than 8 carbons compound because it
25. NMR spectra (Figures a, b, c and d) of four isomers are shown. with formula Cl0HuOr Their infrared spectra show strong bands close to 1735 cm'1, do not interpret the aromatic proton region between 7.0 and 7.5 ppm, except to determine the number of protons attached to the aromatic ring. Draw as structures of compounds.

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