The first ionization potential for S is lower than the first ionization potential for P because: a) p has a p3 configuration b) Hund's rule is violated Oc) ionization potentials decrease across a representative period d) P is below S on the periodic table e) p is to the right of S on the periodic table bonds: a) have very little electron density along the internuclear axis Ob) are formed from s orbitals c) are formed from hybrid orbitals d) are formed by endwise overlap of p orbits e) are the only kind of bonds present in double bonds
The first ionization potential for S is lower than the first ionization potential for P because: a) p has a p3 configuration b) Hund's rule is violated Oc) ionization potentials decrease across a representative period d) P is below S on the periodic table e) p is to the right of S on the periodic table bonds: a) have very little electron density along the internuclear axis Ob) are formed from s orbitals c) are formed from hybrid orbitals d) are formed by endwise overlap of p orbits e) are the only kind of bonds present in double bonds
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The first ionization potential for S is lower than the first ionization potential for P
because:
a) p has a p3 configuration
b) Hund's rule is violated
Oc) ionization potentials decrease across a representative period
d) P is below S on the periodic table
e) p is to the right of S on the periodic table
Transcribed Image Text:bonds:
a) have very little electron density along the internuclear axis
Ob) are formed from s orbitals
c) are formed from hybrid orbitals
d) are formed by endwise overlap of p orbits
e) are the only kind of bonds present in double bonds
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