Chemistry Ash was estimated in the sample of hay, and the records were as follows, note that the moisture is 18%. Weight of crucible = 14 g Weight of crucible + sample = 15.2 g Weight of crucible + ash = 14.1 g ilculate: i. Ash percentage according to the fresh material ii. Ash percentage according to the dry matter iii. Organic matter percentage according to the dry matter iv. Organic matter percentage according to the fresh material

Chemistry Ash was estimated in the sample of hay, and the records were as follows, note that the moisture is 18%. Weight of crucible = 14 g Weight of crucible + sample = 15.2 g Weight of crucible + ash = 14.1 g ilculate: i. Ash percentage according to the fresh material ii. Ash percentage according to the dry matter iii. Organic matter percentage according to the dry matter iv. Organic matter percentage according to the fresh material

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter10: Fuels, Organic Chemicals, And Polymers

Section10.2: U. S/ Energy Sources And Consumption

Problem 10.4E

See similar textbooks

Similar questions

4.3 Explain the difference between complete and incomplete combustion.
5) If all the NaHCO3 in bag 2 reacted, calculate the number of moles of gas produced? tates) E Focus
4. A new procedure for the determination of sulfur in coal was tested on a standard coal sample with a certified value of 2.14% sulfur by mass. The new procedure gave results of 2.11%, 2.07%, 2.04%, 2.06%, and 2.16% for five separate determinations. a) Does the new procedure give the correct result at the 95% confidence level? b) Does the new procedure give the correct result at the 90% confidence level?
ity 7 Problem-Solving! ctions: Show your solution in the space provided. Follow the GFFSA (Given, Find, omula, Solution, Answer) format if possible. Write your answers in the space provided. (5 points each) 1. Combustion of hydrocarbons like methane (CH4) produces two products, water (H2O) and carbon dioxide (CO2). Consider the chemical equation of this combustlon: CH4 + 2 02- CO2 + 2 H20, when 4 mol of CHa reacts with 4 mol of O2, how many moles of CO2 are formed? What is the limiting reactant? 2. How many grams of lead II chloride are produced from the reaction of 16.2 g of NaCl and 62.0 g of Pb(NO3)27 What is the limiting reactant? How much excess is left over?
Gravimetric analysis of Fe3O4 (MW = 232 g/mole) may be undertaken with the following reactions: Fe3O4 → Fe2O3 → Fe (OH)3. Weight of sample containing 8.00% Fe3O4 that must be taken to obtain a precipitate of Fe(OH)3 (MW = 107 g/mole) that weighs 150 mg is . a. 0.108 g b. 0.325 g c. 1.355 g d. 4.065 g Amount of Fe2O3 (MW = 160 g/mole) from which 150 mg of Fe(OH)3 (MW = 107 g/mole) may be obtained is . a. 0.112 g b. 0.224 g c. 0.448 g d. none of the other choices
4) An electric furnace produces Mn from Mn3O4 by reaction with carbon. If 40 kg Mn3O4 reacts with 12 kg of carbon and produces 18 kg Mn, 8 kg MnO, CO gas and some reactants have no reaction, Determine: a. The amount of Mn;04 and C with no reaction in kg. b. The amount of CO in kg is produced. Information: C= 12, 0= 16, Mn=55 40 kg = Mn;O4 CO (gas) Furnace 12 kg = C Mn = 18 kg MnO=8 kg Solid C Mn304
A stock solution of analyte is made by dissolving 34.83 mg of copper (II) acetate hexahydrate(fw = 289.73 g/mol) in 25.00 mL of water. A second stock solution of internal standard is madeby dissolving 28.43 mg of germanium (I) acetate (fw = 190.74 g/mol) into 25.00 mL of water.These solutions are used to make a series of standards for ﬂame atomic absorption analysiscalibration. The standard solutions (each 10.00 mL total volume) should have the followingconcentrations of copper: 10.00; 25.00; 50.00; 100.0; and 200.0 μM. Each calibration solutionshould also contain 50.00 μM of germanium. What is the analyte stock solution concentration? What is the internal standard stocksolution concentration?Complete this table.
A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00-mL volumetric flask "B," which is then diluted with DI H,0 to the calibration mark. The solution is thoroughly mixed. Next, 2.00 mL of the solution in volumetric flask "A" is transferred by pipet to a 50.00-mL volumetric flask "B" and then diluted with DI H,0 to the calibration mark. Calculate the molarity of the solution in vol- umetric flask “B."
4 A model for the compound butane is shown. E 20 F3 D C Submit Answer 4 Write a balanced chemical equation that shows the formation of butane from the elements carbon (C) and hydrogen (H₂ ). (Use the smallest integer coefficients possible and do not include states.) ball & stick-+ labels 200 000 F4 R F + H % 5 V WH [Review Topics] [References] Use the References to access important values if needed for this question. Retry Entire Group 9 more group attempts remaining Cengage Learning Cengage Technical Support F5 T G B MacBook Air F6 Y H & 7 F7 U N * 8 J F8 M ( 9 K DD FO O F12 I } delete
I know how to do the equation, But no matter how I set it up in Chem 101 it says it's not correct. Please help!
Please help me find weight percentage of the unknown solution, Thank you in advance Data attached below: Data of unknown NaCl solution (by weight) weight of weighing bottle and solution: 34.91g weight of weighing bottle: 23.91g weight of the solution: 11.00g Initial buret reading 33.28ml Final buret reading: 43.26ml The volume of the solution; 9.98 ml The density of solution: 1.10 Weight % of unknow solution: ?
yellow there are three question. please square the answers thank you !