A 5.00 g sample of metallic copper (MW: 63.546) is reacted with an excess of oxygen gas (MW: 31.998). The reaction is given by the equation below. Cu(s) + O2(9) –→ CuO(s) Note: Use proper number of significant figures for succeeding questions. Balance the equation. Note: DO NOT USE FRACTIONS. USE THE LOWEST POSSIBLE SET OF COEFFICIENTS 2 |Cu(s) + 1 02 (g) CuO(s) Calculate the theoretical moles and mass of CuO(s) that will be produced from the reaction. moles of CuO theoretical : mol mass of CuO theoretical : g If 4.626 g of product was obtained from the reaction, calculate the yield. yield: %

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A 5.00 g sample of metallic copper (MW: 63.546) is reacted with an excess of oxygen gas (MW: 31.998). The
reaction is given by the equation below.
Cus) + O2(9) → CuO(s)
Note: Use proper number of significant figures for succeeding questions.
Balance the equation.
Note: DO NOT USE FRACTIONS. USE THE LOWEST POSSIBLE SET OF COEFFICIENTS
|Cu(s) + 1
02 (g)
→2
CuO(s)
2
Calculate the theoretical moles and mass of CuO(s) that will be produced from the reaction.
moles of CuO theoretical :
mol
mass of CuO theoretical :
g
If 4.626 g of product was obtained from the reaction, calculate the yield.
yield:
Transcribed Image Text:A 5.00 g sample of metallic copper (MW: 63.546) is reacted with an excess of oxygen gas (MW: 31.998). The reaction is given by the equation below. Cus) + O2(9) → CuO(s) Note: Use proper number of significant figures for succeeding questions. Balance the equation. Note: DO NOT USE FRACTIONS. USE THE LOWEST POSSIBLE SET OF COEFFICIENTS |Cu(s) + 1 02 (g) →2 CuO(s) 2 Calculate the theoretical moles and mass of CuO(s) that will be produced from the reaction. moles of CuO theoretical : mol mass of CuO theoretical : g If 4.626 g of product was obtained from the reaction, calculate the yield. yield:
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