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Charges q1 = q2 = +10.0×10–4C and q3 = -8.0×10–4C are distributed as shown on the right. 1) What is the electric field vector at point C? Remember: magnitude and direction! 2) What is the value of V at point C? ) E=(4 x69)- (2)2 =F1.8N/CI = 1.8 NK downnard direction . +) 2.0 m I+-2.0 m C 2) ver) = -Ex 4x 2.0 m = 8NとCEM) 3.6 93

Charges q1 = q2 = +10.0×10–4C and q3 = -8.0×10–4C are distributed as shown on the right. 1) What is the electric field vector at point C? Remember: magnitude and direction! 2) What is the value of V at point C? ) E=(4 x69)- (2)2 =F1.8N/CI = 1.8 NK downnard direction . +) 2.0 m I+-2.0 m C 2) ver) = -Ex 4x 2.0 m = 8NとCEM) 3.6 93

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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+10.0X10-2 -8.0x10- Charges q1 = q2 = +10.0x10-4C and q3 =-8.0x10-4C are distributed as shown on the right. 1) What is the electric field vector at point C? Remember: magnitude and direction! 2) What is the value of V at point C? ) E = 72)2 =F1.8N/C! = 1.8 NC downwand direction 2.0 m 2) ver) = -Ex 4x 2.0 m 3.6 93
Transcribed Image Text:+10.0X10-2 -8.0x10- Charges q1 = q2 = +10.0x10-4C and q3 =-8.0x10-4C are distributed as shown on the right. 1) What is the electric field vector at point C? Remember: magnitude and direction! 2) What is the value of V at point C? ) E = 72)2 =F1.8N/C! = 1.8 NC downwand direction 2.0 m 2) ver) = -Ex 4x 2.0 m 3.6 93
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