**Educational Content on Car Dynamics in a Banked Turn** A car of mass \( m \) is maneuvering through a circular turn with a radius \( R \). This path is banked at an angle \( \theta \) relative to the horizontal ground, depicted in the diagram provided. The gravitational acceleration is denoted as \( g \). In this scenario, kinetic friction is disregarded, meaning the tires are assumed not to slip. ### Problem Breakdown: #### (a) Critical Speed Without Static Friction Determine the speed \( v_0 \) at which the car must enter the banked turn on a highly slippery road (static friction \( \mu_s = 0 \)) to avoid sliding either up or down the turn. Express \( v_0 \) in terms of \( \theta \), \( g \), and \( R \). #### (b) Sliding Down Due to Static Friction In a situation where static friction (\( \mu_{s1} \)) is a factor but not zero, calculate the speed \( v_a \) at which the car will just begin to slide down the banked turn. The expression should involve \( \theta \), \( g \), \( R \), and \( \mu_{s1} \). #### (c) Sliding Up Due to Static Friction Conversely, when static friction (\( \mu_{s2} \)) is present (not zero), find the speed \( v_a \) at which the car will start to slide up the same banked turn. Express this speed in terms of \( \theta \), \( g \), \( R \), and \( \mu_{s2} \). ### Diagram Explanation: The diagram illustrates a side view of the car on the banked road. The car is oriented with its rear facing the viewer, moving away. The banking angle \( \theta \) is shown, along with the radius \( R \) of the circular path. The vector \( \overrightarrow{v} \) represents the car's velocity. This setup helps visualize the forces at play while navigating the banked curve.
**Educational Content on Car Dynamics in a Banked Turn** A car of mass \( m \) is maneuvering through a circular turn with a radius \( R \). This path is banked at an angle \( \theta \) relative to the horizontal ground, depicted in the diagram provided. The gravitational acceleration is denoted as \( g \). In this scenario, kinetic friction is disregarded, meaning the tires are assumed not to slip. ### Problem Breakdown: #### (a) Critical Speed Without Static Friction Determine the speed \( v_0 \) at which the car must enter the banked turn on a highly slippery road (static friction \( \mu_s = 0 \)) to avoid sliding either up or down the turn. Express \( v_0 \) in terms of \( \theta \), \( g \), and \( R \). #### (b) Sliding Down Due to Static Friction In a situation where static friction (\( \mu_{s1} \)) is a factor but not zero, calculate the speed \( v_a \) at which the car will just begin to slide down the banked turn. The expression should involve \( \theta \), \( g \), \( R \), and \( \mu_{s1} \). #### (c) Sliding Up Due to Static Friction Conversely, when static friction (\( \mu_{s2} \)) is present (not zero), find the speed \( v_a \) at which the car will start to slide up the same banked turn. Express this speed in terms of \( \theta \), \( g \), \( R \), and \( \mu_{s2} \). ### Diagram Explanation: The diagram illustrates a side view of the car on the banked road. The car is oriented with its rear facing the viewer, moving away. The banking angle \( \theta \) is shown, along with the radius \( R \) of the circular path. The vector \( \overrightarrow{v} \) represents the car's velocity. This setup helps visualize the forces at play while navigating the banked curve.
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