Characteristic x-rays of the K series are produced when an electron in an upper energy level of a many- electron atom drops down to fill a vacancy in the K (n = 1) shell. Assuming that the given wavelengths are the three longest wavelengths in the K series of tungsten, the transitions that produce them are from the N (n = 4) shell to the K shell, from the M (n = 3) shell to the K shell, and from the L (n = 2) shell to the K shell, respectively. These transitions are shown in the energy level diagram, where 1, = 0.0185 nm, = 0.0209 nm, and 13 = 0.0215 nm. If the ionization energy of the K shell is 69.5 keV, then EK = -69.5 keV. En N shell Ем M shell EL L shell Ex K shell The photon produced in a transition from an initial state to a final state has energy hc Ephoton Ej - Ef, and therefore the energy of the initial shell is given by the following. hc E; = Ef + Thus, for a transition from the initial state with energy EN to the final state with energy EK, we have hc EN Ек + 6.63 x 10¬34 j•s) 3.00 x 108 kev) + =)(3. m/s 1 keV - (- %3D x 10 m -9 1.60 x 10-16 j kev.
Characteristic x-rays of the K series are produced when an electron in an upper energy level of a many- electron atom drops down to fill a vacancy in the K (n = 1) shell. Assuming that the given wavelengths are the three longest wavelengths in the K series of tungsten, the transitions that produce them are from the N (n = 4) shell to the K shell, from the M (n = 3) shell to the K shell, and from the L (n = 2) shell to the K shell, respectively. These transitions are shown in the energy level diagram, where 1, = 0.0185 nm, = 0.0209 nm, and 13 = 0.0215 nm. If the ionization energy of the K shell is 69.5 keV, then EK = -69.5 keV. En N shell Ем M shell EL L shell Ex K shell The photon produced in a transition from an initial state to a final state has energy hc Ephoton Ej - Ef, and therefore the energy of the initial shell is given by the following. hc E; = Ef + Thus, for a transition from the initial state with energy EN to the final state with energy EK, we have hc EN Ек + 6.63 x 10¬34 j•s) 3.00 x 108 kev) + =)(3. m/s 1 keV - (- %3D x 10 m -9 1.60 x 10-16 j kev.
Related questions
Question
Transcribed Image Text:The K series of the discrete spectrum of tungsten contains wavelengths of 0.0185 nm, 0.0209 nm, and 0.0215
nm. The K-shell ionization energy is 69.5 keV. Determine the ionization energies of the L, M, and N shells.
Step 1
Characteristic x-rays of the K series are produced when an electron in an upper energy level of a many-
electron atom drops down to fill a vacancy in the K (n = 1) shell. Assuming that the given wavelengths are
the three longest wavelengths in the K series of tungsten, the transitions that produce them are from the N
(n
4) shell to the K shell, from the M (n = 3) shell to the K shell, and from the L (n
= 2) shell to the K shell,
respectively. These transitions are shown in the energy level diagram, where 1, = 0.0185 nm,
= 0.0209 nm, and 13
12
EK
= 0.0215 nm. If the ionization energy of the K shell is 69.5 keV, then
= -69.5 keV.
En
N shell
EM
M shell
EL
L shell
Ex-
K shell
The photon produced in a transition from an initial state to a final state has energy
hc
Ephoton
E¡ - Ef,
and therefore the energy of the initial shell is given by the following.
hc
E; = Ef +
Thus, for a transition from the initial state with energy EN to the final state with energy EK, we have
hc
EN = EK +
6.63 x 10-34 J•s3.00 x 108 m/s
J.S
1 kev
- (-
kev) -
+
x 10-9 m)
1.60 x 10-16
kev.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
