Chapter 15, Problem 049 The angle (with respect to the vertical) of a simple pendulum is given by e = emcos[(4.96 rad/s)t ]. If at t 0.0350 rad and de/dt = -0.240 rad/s, what are (a) the phase constant o and (b) the maximum angle 8m? (Hint: Don't confuse 0, e the rate d0/dt at which 8 changes with the w of the SHM.) Pivot point 1е\ -Fcose sine (a) (b) (a) Number Unit (b) Number Unit

Chapter 15, Problem 049 The angle (with respect to the vertical) of a simple pendulum is given by e = emcos[(4.96 rad/s)t ]. If at t 0.0350 rad and de/dt = -0.240 rad/s, what are (a) the phase constant o and (b) the maximum angle 8m? (Hint: Don't confuse 0, e the rate d0/dt at which 8 changes with the w of the SHM.) Pivot point 1е\ -Fcose sine (a) (b) (a) Number Unit (b) Number Unit

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Chapter 15, Problem 049
The angle (with respect to the vertical) of a simple pendulum is given by e = emcos[(4.96 rad/s)t ]. If at t
0.0350 rad and de/dt = -0.240 rad/s, what are (a) the phase constant o and (b) the maximum angle 8m? (Hint: Don't confuse
0, e
the rate d0/dt at which 8 changes with the w of the SHM.)
Pivot
point
1е\
-Fcose
sine
(a)
(b)
(a) Number
Unit
(b) Number
Unit

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The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(5.88 rad/s)t + $]. If at t = 0,0 = 0.0450 rad and de/dt = -0.160 rad/s, what are (a) the phase constant p and (b) the maximum angle em? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.) Pivot point L. e\L S= Le F, cose Fesine- (a) (b) (a) Number i Unit (b) Number Unit >