Chapter 15, Problem 049 GOThe angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.40 rad/s)t + p]. If at t = 0, 0 = 0.0200 rad and de/dt = -0.160 rad/s, what are (a)the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.)PivorpointL.Is= LeF,coseFgsine-(a)(6)(a) NumberUnit(b) Number the tolerance is +/-2%UnitClick if you would like to Show Work for this question:Open Show Work

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