The angle (with respect to the vertical) of a simple pendulum is given by e = Omcos[(5.88 rad/s)t + p]. If at t = 0, 0 = 0.0450 rad and de/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle Om? (Hint: Don't confuse the rate d0/dt at which 0 changes with the w of the SHM.)

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The angle (with respect to the vertical) of a simple pendulum is given by 0
= 0mcos[(5.88 rad/s)t + p]. If at t = 0, 0 = 0.0450 rad and d0/dt = -0.160 rad/s, what are (a) the
phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate d0/dt at which 0
changes with the w of the SHM.)
Pivot
point
L.
1e\L
Is= LO
F,cose
Fgsine
(a)
(b)
Transcribed Image Text:The angle (with respect to the vertical) of a simple pendulum is given by 0 = 0mcos[(5.88 rad/s)t + p]. If at t = 0, 0 = 0.0450 rad and d0/dt = -0.160 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate d0/dt at which 0 changes with the w of the SHM.) Pivot point L. 1e\L Is= LO F,cose Fgsine (a) (b)
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