Change Summation Integers problem to Finding the minimum problem. Move System.out.print statements, displaying results inside the methods, making all your methods VOID.

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Change Summation Integers problem to Finding
the minimum problem. Move System.out.print statements, displaying results inside the methods,
making all your methods VOID.

3 import java.util.Scanner;
5 public class ReportSum4 {
public static void main(String args[]) {
Scanner sc = new Scanner (System. in);
// Prompt the user to enter the number of integers
System.out.println("Enter the number of integers you will provide: ");
int num - sc.nextInt();
12
// Prompt the user to enter the first integer
System.out.println("Enter the value for 'a' and press Enter: ");
int a =
13
14
15
sc.nextInt();
// Prompt the user to enter the second integer
System.out.println("Enter the value for 'b' and press Enter: ");
int b = sc.nextInt();
16
18
if (num =- 3) {
// Prompt the user to enter the third integer
System.out.println("Enter the value for 'c' and press Enter: ");
int c =
// Display the result
System.out.printf( "Provided Integers: %4d and %4d and %4d, the total is %5d\n", a, b, c, sum(a, b, c));
20
sc. nextInt();
élse {
// Display the result
System.out.printf( "Provided Integers: %4d and %4d, the total is %5d\n", a, b, sum(a, b));
}
public static int sum(int num1, int num2){
return numl + num2;
31
320
33
34
350
public static int sum(int num1, int num2, int num3){
36
return numl + num2 + num3;
}
38 }
39 |
37
Our client just contacted us and said that they are planning from time to time provide us four integers instead
of two and three
Hint: What would be a universal/generic solution for dealing with such clients? Should we be proactive and
write methods with 5, 6, 7, etc. parameters in advance?
Transcribed Image Text:3 import java.util.Scanner; 5 public class ReportSum4 { public static void main(String args[]) { Scanner sc = new Scanner (System. in); // Prompt the user to enter the number of integers System.out.println("Enter the number of integers you will provide: "); int num - sc.nextInt(); 12 // Prompt the user to enter the first integer System.out.println("Enter the value for 'a' and press Enter: "); int a = 13 14 15 sc.nextInt(); // Prompt the user to enter the second integer System.out.println("Enter the value for 'b' and press Enter: "); int b = sc.nextInt(); 16 18 if (num =- 3) { // Prompt the user to enter the third integer System.out.println("Enter the value for 'c' and press Enter: "); int c = // Display the result System.out.printf( "Provided Integers: %4d and %4d and %4d, the total is %5d\n", a, b, c, sum(a, b, c)); 20 sc. nextInt(); élse { // Display the result System.out.printf( "Provided Integers: %4d and %4d, the total is %5d\n", a, b, sum(a, b)); } public static int sum(int num1, int num2){ return numl + num2; 31 320 33 34 350 public static int sum(int num1, int num2, int num3){ 36 return numl + num2 + num3; } 38 } 39 | 37 Our client just contacted us and said that they are planning from time to time provide us four integers instead of two and three Hint: What would be a universal/generic solution for dealing with such clients? Should we be proactive and write methods with 5, 6, 7, etc. parameters in advance?
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