CH4(g) + CCI4(g) 2CH2C12(g) When she introduced 4.30x10-2 moles of CH4(g) and 7.96x10-2 moles of CCI4(g) into a 1.00 liter container, she found the equilibrium concentration of CH2CI2(g) to be 2.04×10-2 M. Calculate the equilibrium constant, Ke, she obtained for this reaction.

Q: NO(g) and 0.160 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration…

A: From the given values,     2NO Br2 2NOBr I 0.218 0.160 0 C -2x -x +2x E 0.218-2x 0.160-x 2x…

Q: Calculating equilibrium composition from an equilibrium constant Suppose a 250. mL flask is filled…

A:

Q: A student ran the following reaction in the laboratory at 703 K:      H2(g) + I2 (g) = 2HI (g) When…

A: The objective of the question is to calculate the equilibrium constant, Kc, for the reaction H2(g) +…

Q: A student ran the following reaction in the laboratory at 337 K: 2NO(g) + Br2 (g) = 2NOBr(g) When…

A:

Q: A student ran the following reaction in the laboratory at 652 K: 2NH3(g) N2(g) + 3H2(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 617 K: Co(g) + Cl2(g) = cocl2(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 666 K: 2NH3(9) ? N₂(g) + 3H₂(g) When she…

A:

Q: Tabo PC13 (g) + Cl₂ (g) ⇒ PC15 (9) she introduced 0.0811 moles of PC13 (9) and d the equilibrium…

A:

Q: 3 A(g) + B(g) = 2C(g) + 2 D(g)

A: Equilibrium constant is defined as the ratio of product of concentration of products to that of…

Q: A student ran the following reaction in the laboratory at 529 K: COC12 (9)CO(g) + Cl₂ (9) When she…

A: The equilibrium constant of a reaction is defined as the ratio of the concentration of products to…

Q: A student ran the following reaction in the laboratory at 635 K: 2 HI (g)  H2 (g) + I2 (g) When…

A: Moles of HI introduced = 0.404 Volume of container = 1.00L Concentration of HI =…

Q: A student ran the following reaction in the laboratory at 290 K: 2CH2CI2(g) =CH4(g) + CCI4(g) When…

A:

Q: A student ran the following reaction in the laboratory at 547 K: COCl2 = CO+ Cl2 When she introduced…

A: The objective of the question is to calculate the equilibrium constant, Kc, for the reaction COCl2 =…

Q: A student ran the following reaction in the laboratory at 668 K: H2(g) + I2(g) 2HI(g) When she…

A: The concentration of a solution can be defined in terms of molarity as the ratio of the amount of…

Q: The compound NOCl decomposes to nitric oxide and chlorine according to the following equation: 2…

A: Given, 2 NOCl (g) → 2 NO (g) + Cl2 (g) Initially moles of NOCl = 0.510 mol Volume of the flask =…

Q: The chemical equilibrium, 2A(g) = B(g) + C(g) has a Kc of 0.0460. Calculate the equilibrium…

A: Given reaction is, 2Ag⇌Bg+Cg Initial concentration of A, B and C is, [A] = 0.450 M, [B] = 0.330 M,…

Q: student ran the following reaction in the laboratory at 292 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: The question is based on the principle equilibrium. we have been given equilibrium concentration of…

Q: A student ran the following reaction in the laboratory at 540 K: COC12 (g) CO(g) + Cl₂ (g) When she…

A: Reaction COCl2(g) -------->CO(g) + Cl2(g)

Q: 111 Catruteting equilibrium composition from an equilibrium constant Suppose a 250. ml. flask is…

A:

Q: A student ran the following reaction in the laboratory at 534 K: CoCI2 (g) co (g) + Cl2 (g) When she…

A:

Q: A student ran the following reaction in the laboratory at 244 K: 2NOBr(g) =2NO(g) + Br2(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 666 K:2NH3(g) N2(g) + 3H2(g)When she…

A:

Q: A student ran the following reaction in the laboratory at 288 K: 2CH₂Cl₂(9) CH4(9) + CCl4(9) When…

A:

Q: A student ran the following reaction in the laboratory at 682 K: H₂(g) + 12 (9) 2HI(g) When she…

A: The relation between the concentrations of products and reactants is related by a term known as…

Q: If 1.34 moles each of Br2 and Cl2 are introduced into an 11.0 liter flask and allowed to come to…

A: Consider the given information is as follows; Initial moles of Br2 = 1.34 mol Moles of of Cl2 = 1.34…

Q: A student ran the following reaction in the laboratory at 545 K: COC12 (g) CO(g) + Cl₂ (g) When she…

A:

Q: A student ran the following reaction in the laboratory at 538 K: COCl2(g) CO(g) + Cl2(g) When she…

A:

Q: Consider the following reaction: Part A CO (g) + 2 H2 (g) = CH3OH (g) What is the value of the…

A:

Q: A student ran the following reaction in the laboratory at 290 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: The chemical equation :  2CH2Cl2(g)  ----> CH4(g) + CCl4(g)  Number of moles of CH2Cl2 = 8.37…

Q: Given the following chemical system: 4NH3(s) + 502(g) → 4NO(g) + 6H2O(g) If 0.35 mol of both…

A: The equilibrium concentration with equilibrium constant can be calculated as :-

Q: A student ran the following reaction in the laboratory at 651 K: 2NH3(g) N2(g) + 3H2(g) When she…

A: The given reaction is:                    2NH3  (g) ⇌         N2 (g)    +   3H2 (g)Initial…

Q: A student ran the following reaction in the laboratory at 286 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: 2CH2Cl2(g)     =     CH4(g)       +   CCl4(g) Kc = [CH4][CCl4]/[CH2Cl2]2

Q: A student ran the following reaction in the laboratory at 544 K: COC1₂ (9) CO(g) + Cl₂ (g) When she…

A: It is based on the concept of chemical equilibrium   Here we are required to find the equilibrium…

Q: A student ran the following reaction in the laboratory at 672 K: 2NH3(g)     N2(g) + 3H2(g) When…

A:

Q: A student ran the following reaction in the laboratory at 281 K: 2 CH2CI2 (g) = CH4 (g) + CCl4 (g)…

A:

Q: A student ran the following reaction in the laboratory at 431 K: PCI 5(9) PC13(g) + Cl₂(9) When she…

A: Given, the equilibrium reaction as follows, PCl5(g) ⇌ PCl5(g)+Cl2 (g) with initial amount of PCl5…

Q: A student ran the following reaction in the laboratory at 70 K: H2(g) + I2(g) 2HI(g) When she…

A:

Q: A student ran the following reaction in the laboratory at 282 K: 2CH,Cl½(g) CH4(g) + CC14(g) When…

A: Given data,Initial moles of CH2Cl2=6.98×10-2molVolume of container=1.0LEquilibrium concentration of…