The equilibrium constant, Kc, for the following reaction is6.93 x 104 at 438 K.PC15 (9)PC13 (g) + Cl₂ (9)When a sufficiently large sample of PC15 (g) is introduced into anevacuated vessel at 438 K, the equilibrium concentration of C1₂ (g) isfound to be 0.246 M.Calculate the concentration of PC15 in the equilibrium mixture.[PC15] =M A student ran the following reaction in the laboratory at 650 K:H₂ (9) + 1₂ (9) 2HI(g)When she introduced 0.224 moles of H₂ (g) and 0.238 moles of I2 (9)into a 1.00 liter container, she found the equilibrium concentration ofHI(g) to be 0.368 M.Calculate the equilibrium constant, K, she obtained for this reaction.K

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The equilibrium constant, Kc, for the following reaction is 6.93 x 104 at 438 K. PC15 (9)PC13 (9) + Cl₂ (9) When a sufficiently large sample of PC15 (9) is introduced into an evacuated vessel at 438 K, the equilibrium concentration of Cl₂ (g) is found to be 0.246 M. Calculate the concentration of PC15 in the equilibrium mixture. [PC15] = M

The equilibrium constant, Kc, for the following reaction is 6.93 x 104 at 438 K. PC15 (9)PC13 (9) + Cl₂ (9) When a sufficiently large sample of PC15 (9) is introduced into an evacuated vessel at 438 K, the equilibrium concentration of Cl₂ (g) is found to be 0.246 M. Calculate the concentration of PC15 in the equilibrium mixture. [PC15] = M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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