CH3 H3C. CH3 Br HBr CH2 CH3 H3C H3C ČH3 Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the a electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior to the last step in order to form a more stable carbocation. In the final step of the reaction, nucleophilic bromide adds to the carbocation to give the neutral product. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 H3C. CH3 CH3 H3C H3C ČH3 Submit Answer Retry Entire Group 9 more group attempts remaining

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Chapter1: Chemical Foundations
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CH3
H3C.
CH3
Br
HBr
CH2
CH3
H3C
H3C
ČH3
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the T
electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp carbon
containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring
hydride or methyl group can occur prior to the last step in order to form a more stable carbocation. In the final step of the reaction, nucleophilic
bromide adds to the carbocation to give the neutral product.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
CH3
CH3
H3C.
CH3
.CH3
H3C°
H3C°
ČH3
Submit Answer
Retry Entire Group
9 more group attempts remaining
Transcribed Image Text:CH3 H3C. CH3 Br HBr CH2 CH3 H3C H3C ČH3 Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the T electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior to the last step in order to form a more stable carbocation. In the final step of the reaction, nucleophilic bromide adds to the carbocation to give the neutral product. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 H3C. CH3 .CH3 H3C° H3C° ČH3 Submit Answer Retry Entire Group 9 more group attempts remaining
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