Any help with this would be great! Explanations definitely welcome, thank you in advance:) What is the product of the reactions? ### Reaction Mechanism: Hydration of Cyclopentene**Overview:**The image depicts a chemical reaction involving cyclopentene and deuterated methanol (CH₃OD) in the presence of a hydrogen ion (H⁺) catalyst. The reaction displays four possible products resulting from the addition of deuterium (D) and methoxy groups (OCH₃).**Reaction Details:**- **Starting Materials:** - Cyclopentene: A five-membered carbon ring with a double bond. - Deuterated Methanol: CH₃OD, where "D" represents deuterium, an isotope of hydrogen.- **Catalyst:** - Hydrogen ion (H⁺): Facilitates the reaction.---**Possible Reaction Products:**- **a)** Addition of deuterium (D) and a hydrogen atom: - The double bond in cyclopentene is broken, and a deuterium atom is added to one carbon while a hydrogen atom is added to the adjacent carbon.- **b)** Addition of hydroxyl (OH) and hydrogen (H): - Similar to product (a), but adds an OH group instead of D.- **c)** Addition of deuterium (D) and methoxyl (OCH₃): - The deuterium atom adds to one carbon, while the methoxy group adds to the adjacent carbon.- **d)** Addition of hydroxy (OH) and methoxyl (OCH₃): - The OH group is added to one carbon, while the methoxy group is added to the other.---**Diagrams:**Each structure shows the cyclopentane ring with the new substituents:- Product *(a)* shows a D atom and an additional H atom.- Product *(b)* shows an OH group and an H atom.- Product *(c)* shows D and OCH₃ groups.- Product *(d)* shows OH and OCH₃ groups.These variations highlight the possible regioselectivity in nucleophilic attack and addition. **Title: Reaction Mechanisms in Organic Chemistry****Introduction:**This educational module explores the reaction of a cyclic ketone with hydrochloric acid (HCl), leading to potential rearrangement of substituents. Understanding these transformations is crucial for students studying organic chemistry.**Reaction Details:**- **Starting Material:** A six-membered cyclic ketone with a methyl group (CH₃) attached at the alpha position. - **Reagent:** Hydrochloric acid (HCl).- **Question:** What is the major product of this reaction?**Potential Products:**1. **Product (a):** Shows the chloride (Cl) group added on the cyclohexane ring adjacent to the carbon with the methyl group and opposite the carbonyl group (O). The methyl group is positioned on a wedge, indicating it is above the plane, and the chloride is on a dash, indicating it is below the plane.2. **Product (b):** Depicts the chloride (Cl) group added similarly on the cyclohexane ring but swapping the relative positions compared to Product (a): the chloride is on a wedge, and the methyl group is on a dash.**Options to Determine the Correct Product:**A. Product (a) B. Product (b) C. Both products D. Neither product**Explanation:**This exercise requires the student to apply knowledge of stereochemistry and reaction mechanisms, particularly understanding nucleophilic addition to the carbonyl group and subsequent stereochemical outcomes. The correct answer involves evaluating the stereochemical implications of adding HCl to the starting material.**Graphical Elements:**The diagram illustrates a common organic reaction and its possible stereochemical products, a vital skill for interpreting molecular structures and predicting reaction outcomes in organic synthesis.

Since you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.The first equation involves reaction between methylcylopentene and methanol in presence of H+. As H+ is present, it will be attacked by pi electron cloud of double bond to form carbocation and addition of methanol will follow Markownikov's rule. As per this rule, the negative part (electron rich part) of the addendum will go to that carbon of double bond which has less number of hydrogen atoms. The mechanism involved is as shown below: In above mechanism, H+) may add on to any of the doubly bonded carbon forming either secondary (if it adds to methyl bearing carbon) or tertiary (if it adds to H bearing carbon). As tertiary carbocation is more stable, it is preferably formed. As product matches with that of d), so, correct choice is option d.