CH3 B. CH3 CH3 CH3 H3C-0® CH3 CH3 `CH3 H3CO CH3 dimethyl ether trimethylborane а. ether complexed borane Lewis acid of the reaction above is Lewis base of the reaction above is

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Identify the Lewis acid and Lewis base in the organic reactions (on the reactant side) below

 

### Understanding Lewis Acids and Bases

In the given reaction, trimethylborane (\( B(CH_3)_3 \)) reacts with dimethyl ether (\( (CH_3)_2O \)) to form an ether complexed borane.

#### Reaction Overview:

1. **Reactants:**
   - **Trimethylborane (\( B(CH_3)_3 \))**: This molecule has an electron-deficient boron atom.
   - **Dimethyl ether (\( (CH_3)_2O \))**: This molecule has a lone pair of electrons on the oxygen atom.

2. **Product:**
   - **Ether complexed borane**: The oxygen in dimethyl ether donates its lone pair of electrons to the boron in trimethylborane, forming a coordinate covalent bond. This changes the structure and charge arrangement of the molecules involved.

   **Diagram Description:**
   The diagram shows the electron-pair donation from dimethyl ether to trimethylborane. An arrow indicates this movement of electrons. In the product, the oxygen in dimethyl ether is coordinated to boron, forming a complex.

#### Questions:

1. **Lewis acid of the reaction above is:**
   \[ \boxed{\text{Trimethylborane} \hspace{8pt} (B(CH_3)_3)} \]

   **Explanation:**
   A Lewis acid is a molecule that can accept an electron pair. In this reaction, the boron atom in trimethylborane accepts a pair of electrons from the oxygen in dimethyl ether.

2. **Lewis base of the reaction above is:**
   \[ \boxed{\text{Dimethyl ether} \hspace{8pt} ((CH_3)_2O)} \]

   **Explanation:**
   A Lewis base is a molecule that can donate an electron pair. In this reaction, the oxygen atom in dimethyl ether donates a pair of electrons to the boron in trimethylborane.

This reaction is a classic example of Lewis acid-base interaction, where the Lewis base donates electrons to the Lewis acid, forming a new chemical complex.
Transcribed Image Text:### Understanding Lewis Acids and Bases In the given reaction, trimethylborane (\( B(CH_3)_3 \)) reacts with dimethyl ether (\( (CH_3)_2O \)) to form an ether complexed borane. #### Reaction Overview: 1. **Reactants:** - **Trimethylborane (\( B(CH_3)_3 \))**: This molecule has an electron-deficient boron atom. - **Dimethyl ether (\( (CH_3)_2O \))**: This molecule has a lone pair of electrons on the oxygen atom. 2. **Product:** - **Ether complexed borane**: The oxygen in dimethyl ether donates its lone pair of electrons to the boron in trimethylborane, forming a coordinate covalent bond. This changes the structure and charge arrangement of the molecules involved. **Diagram Description:** The diagram shows the electron-pair donation from dimethyl ether to trimethylborane. An arrow indicates this movement of electrons. In the product, the oxygen in dimethyl ether is coordinated to boron, forming a complex. #### Questions: 1. **Lewis acid of the reaction above is:** \[ \boxed{\text{Trimethylborane} \hspace{8pt} (B(CH_3)_3)} \] **Explanation:** A Lewis acid is a molecule that can accept an electron pair. In this reaction, the boron atom in trimethylborane accepts a pair of electrons from the oxygen in dimethyl ether. 2. **Lewis base of the reaction above is:** \[ \boxed{\text{Dimethyl ether} \hspace{8pt} ((CH_3)_2O)} \] **Explanation:** A Lewis base is a molecule that can donate an electron pair. In this reaction, the oxygen atom in dimethyl ether donates a pair of electrons to the boron in trimethylborane. This reaction is a classic example of Lewis acid-base interaction, where the Lewis base donates electrons to the Lewis acid, forming a new chemical complex.
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