ch loop outputs all of the elements c int i; for( i = 0; i <= 20; ++i) %3D { cout << v.at(i) « endl;
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correct answer will be
int i;
for( i=0 ; i<=20; ++i)
{
cout<< vector.at(i) <<endl;
}
Explanation:
In order to print up to 20 we need to take greater than equal to symbol so that it can reach to 20.
In vectors we need to use vector keyword in defining the particular vectors.
Step by step
Solved in 2 steps
- ] ] has_perfect You are to write a function has "perfect (graph)" that takes in a BIPARTITE graph as its input, and then determintes whether or not the graph has a perfect matching. In other words, it will return the Boolean value True if it has one, and False if it does not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (has perfect({"A" : ["B", "C"], "B" : ["A", "D"], "C" : ["A", "D"], "D" : ["B", "C"]}), has perfect ( {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E": ["B","C","F"], "F":["E"]})) This should return True False Python Python#include <bits/stdc++.h> using namespace std; struct Employee { string firstName; string lastName; int numOfHours; float hourlyRate; char major[2]; float amount; Employee* next; }; void printRecord(Employee* e) { cout << left << setw(10) << e->lastName << setw(10) << e->firstName << setw(12) << e->numOfHours << setw(12) << e->hourlyRate << setw(10) << e->amount << setw(9) << e->major[0]<< setw(7) << e->major[1]<<endl; } void appendNode(Employee*& head, Employee* newNode) { if (head == nullptr) { head = newNode; } else { Employee* current = head; while (current->next != nullptr) { current = current->next; } current->next = newNode; } } void displayLinkedList(Employee* head) { Employee* current = head; if(current!=nullptr){ cout…For the following main functionint _tmain(int argc, _TCHAR* argv[]){int years[10]={2007,2008,2009,2010,2011,2012,2013,2014,2015,2016};cout<<"Years before updating: "<<endl;for(int i=0;i<10;i++){cout<<*(years+i)<<"\t";}cout<<endl;after_2_years(years);cout<<"Years after updating: "<<endl;for(int i=0;i<10;i++){cout<<*(years+i)<<"\t";}cout<<endl;printf("Press any key to continue,...");char ch = getch();return 0;}The result of running the program is as followsYears before updating:2007 2008 2009 2010 2011 2012 2013 2014 2015 2016Years after updating:2009 2010 2011 2012 2013 2014 2015 2016 2017 2018Press any key to continue,...Write the body of function after_2_years()
- #include <iostream>//#include <vector> using namespace std; class Vec {public:Vec() {sz = 0;cap = 1;p_arr = new int[cap];} int size(){return this->sz;}int capacity(){return this->cap;}void reserve( int n ){// TODO:// (0) check the n should be > size, otherwise// ignore this action.if ( n > sz ){// (1) create a new int array which size is n// and get its address//cout << "Adress:"<< &n << endl;int *newarr = new int [n];//cout << "Address: " << newarr << endl; // location // (2) use for loop to copy the old array to the// new arrayfor(int i = 0; i < sz; i++){newarr[i] = p_arr[i];}// (3) update the variable to the new addressthis->cap=n; // (4) delete old arraydelete[] newarr;}}void push_back( int v ){// TODO:if ( sz == cap ){ cap *= 2; reserve(cap);}p_arr[sz++] = v;// complete others}int at(int idx){return this->p_arr[idx];}private://vector<int> arr;int *p_arr;int sz = 0;int cap = 0; }; int main(){Vec v;…#include <iostream> using namespace std; int main(){ int a[100],n,i,item,loc=0; cout<<"Enter number of elements: "; cin>>n; cout<<"\nEnter numbers:\n"; for(i=1;i<=n;i++) { cin>>a[i]; } cout<<"\nEnter number to search:"; cin>>item; for(i=1;i<=n;i++) { if(item==a[i]) { loc=i; break; } } if(loc>0) { cout<<loc<<" is the location of item"; } else cout<<"\nno. not found";} Q: edit the code that shows after how many number of iteration searched value is found#include <iostream>#include <vector>using namespace std; void PrintVectors(vector<int> numsList) { unsigned int i; for (i = 0; i < numsList.size(); ++i) { cout << numsList.at(i) << " "; } cout << endl;} int main() { vector<int> numsList; int userInput; int i; for (i = 0; i < 3; ++i) { cin >> userInput; numsList.push_back(userInput); } numsList.erase(numsList.begin()+1); numsList.insert(numsList.begin()+1, 102); numsList.insert(numsList.begin()+1, 100); PrintVectors(numsList); return 0;} Not all tests passed clearTesting with inputs: 33 200 10 Output differs. See highlights below. Special character legend Your output 33 100 102 10 Expected output 100 33 102 10 clearTesting with inputs: 6 7 8 Output differs. See highlights below. Special character legend Your output 6 100 102 8 Expected output 100 6 102 8 Not sure what I did wrong but the the 33…
- What input or parameter value impacts the number of times the recursive function will be called. • Give three specific examples of input/parameter values and, for each, state the number of times the recursive function will be called. • Devise a formula with respect to n that describes the number of times the recursive function will be called, where n is either the value passed or some property of the value passed (e.g. n might be the length of a string of the size of an array).cout << setw(20) << this->words[i].getWord() << "\t" << this->words[i].getFrequency() << endl; This code keeps giving me errors "class word have no member getfrequency"// Assume all libraries are included 3 void func (int a, int &b, int &c); // int main () { int i = 5, j = 4, k = 33; 4 7 %3D 8. func (i, j, k); func (j, i, k); cout << j « k << i <« endl; 10 11 12 13 return 0; 14 } // 15 16 void func (int a, int &b, int &c) { 17 18 = 2*c + b; 19 b a; 20 C = a + 3*b; } // 21 22 I|||
- 5- int arr[4]= {2, 4, 5, 3); for (int i= 0; i<4; i++) cout<#include<iostream>using namespace std;const int rows=10;const int columns=10;int computer_board1[rows][columns];int computer_board2[rows][columns];int player_board[rows][columns];int x,y;void setboard(){for(int i=0;i<rows;i++){for(int j=0;j<columns;j++){computer_board1[i][j]=0;player_board[i][j]=0;}}}void display_computer_board1(){cout<<"Computer's Board"<<endl;cout<<" 0 1 2 3 4 5 6 7 8 9 "<<endl;for(int i=0;i<rows;i++){for(int j=0;j<columns;j++){if(j==0){cout<<i<<" ";}cout<<computer_board1[i][j]<<" "; }cout<<endl;}cout<<endl;}void display_player_board(){cout<<"Your Board"<<endl;cout<<" 0 1 2 3 4 5 6 7 8 9 "<<endl;for(int i=0;i<rows;i++){for(int j=0;j<columns;j++){if(j==0){cout<<i<<" ";}cout<<player_board[i][j]<<" "; } cout<<endl;} }void place_player_ships(){for(int i=1;i<=15;i++){cout<<"Horizontal…#include <iostream>#include <cstdlib>#include <time.h>#include <chrono> using namespace std::chrono;using namespace std; void randomVector(int vector[], int size){ for (int i = 0; i < size; i++) { //ToDo: Add Comment vector[i] = rand() % 100; }} int main(){ unsigned long size = 100000000; srand(time(0)); int *v1, *v2, *v3; //ToDo: Add Comment auto start = high_resolution_clock::now(); //ToDo: Add Comment v1 = (int *) malloc(size * sizeof(int *)); v2 = (int *) malloc(size * sizeof(int *)); v3 = (int *) malloc(size * sizeof(int *)); randomVector(v1, size); randomVector(v2, size); //ToDo: Add Comment for (int i = 0; i < size; i++) { v3[i] = v1[i] + v2[i]; } auto stop = high_resolution_clock::now(); //ToDo: Add Comment auto duration = duration_cast<microseconds>(stop - start); cout << "Time taken by function: " << duration.count()…SEE MORE QUESTIONS