Certain bacteria can respire in anoxic environments using arsenic (V) as electron acceptor. The relevant unbalance half reactions are: H₂AsO+H* - H¸AsO¸ +H₂O‚logK = 10.84, AG = -14.5kca 4 Lol-e CH₂O+H₂O m - 0 1 + CO2 (g),logK = 1.2, AG˚ = -1.63kca -—-ol-e 1) Balance the two half reactions 2) What is m the overall respiration reaction, standard free energy change \Delta GO 3) Is this process energetically more or less favorable than sulfate reduction? (\Delta GO for the reduction of sulfate to HS- is -5.78 kcal/mol - e-) 4) If [H2ASO4-] = [ H3ASO3] 0.5 mM and pH = 7, estimate pe of the system
Certain bacteria can respire in anoxic environments using arsenic (V) as electron acceptor. The relevant unbalance half reactions are: H₂AsO+H* - H¸AsO¸ +H₂O‚logK = 10.84, AG = -14.5kca 4 Lol-e CH₂O+H₂O m - 0 1 + CO2 (g),logK = 1.2, AG˚ = -1.63kca -—-ol-e 1) Balance the two half reactions 2) What is m the overall respiration reaction, standard free energy change \Delta GO 3) Is this process energetically more or less favorable than sulfate reduction? (\Delta GO for the reduction of sulfate to HS- is -5.78 kcal/mol - e-) 4) If [H2ASO4-] = [ H3ASO3] 0.5 mM and pH = 7, estimate pe of the system
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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![Certain bacteria can respire in anoxic environments using arsenic (V) as electron acceptor. The relevant unbalance half
reactions are: H₂ AsO+H → H¸AsO +H₂O, logK = 10.84, AG = -14.5kca
I
m
I
ol-e CH₂O+H₂OH + CO2 (g), logK = 1.2, AG° = -1.63kca — ol-e 1) Balance the two half reactions 2) What is
m
the overall respiration reaction, standard free energy change \Delta GO 3) Is this process energetically more or less
favorable than sulfate reduction? (\Delta GO for the reduction of sulfate to HS- is -5.78 kcal/mol - e-) 4) If [H2AsO4-] = [
H3ASO3] = 0.5 mM and pH = 7, estimate pe of the system](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57f91ba9-d6f2-4b0c-8cb3-7ae85e2f3b2e%2Fde8de1c3-7d94-46b1-a2de-5197990329c6%2Fw5dfhid_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Certain bacteria can respire in anoxic environments using arsenic (V) as electron acceptor. The relevant unbalance half
reactions are: H₂ AsO+H → H¸AsO +H₂O, logK = 10.84, AG = -14.5kca
I
m
I
ol-e CH₂O+H₂OH + CO2 (g), logK = 1.2, AG° = -1.63kca — ol-e 1) Balance the two half reactions 2) What is
m
the overall respiration reaction, standard free energy change \Delta GO 3) Is this process energetically more or less
favorable than sulfate reduction? (\Delta GO for the reduction of sulfate to HS- is -5.78 kcal/mol - e-) 4) If [H2AsO4-] = [
H3ASO3] = 0.5 mM and pH = 7, estimate pe of the system
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