ccompanying data set and construct a 95% confidence interval estimate of the mean pulse rate of adult females; then do the same for adult males. Compare the results. a. Construct a 90% confidence interval of the mean pulse rate for adult females. (Round to one decimal place as needed.)
ccompanying data set and construct a 95% confidence interval estimate of the mean pulse rate of adult females; then do the same for adult males. Compare the results. a. Construct a 90% confidence interval of the mean pulse rate for adult females. (Round to one decimal place as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Refer to the accompanying data set and construct a 95% confidence
a. Construct a 90% confidence interval of the mean pulse rate for adult females.
(Round to one decimal place as needed.)
b. Construct a 90% confidence interval of the mean pulse rate for adult males.
(Round to one decimal place as needed.)
Expert Solution
Step 1
For males (x1) :
Sample | Males (x1) | (x1x̄1)2 | |
1 | 84 | 282.2400 | |
2 | 74 | 46.2400 | |
3 | 52 | 231.0400 | |
4 | 61 | 38.4400 | |
5 | 53 | 201.6400 | |
6 | 62 | 27.0400 | |
7 | 54 | 174.2400 | |
8 | 77 | 96.0400 | |
9 | 52 | 231.0400 | |
10 | 59 | 67.2400 | |
11 | 70 | 7.8400 | |
12 | 58 | 84.6400 | |
13 | 65 | 4.8400 | |
14 | 75 | 60.8400 | |
15 | 80 | 163.8400 | |
16 | 67 | 0.0400 | |
17 | 66 | 1.4400 | |
18 | 95 | 772.8400 | |
19 | 41 | 686.4400 | |
20 | 85 | 316.8400 | |
21 | 73 | 33.6400 | |
22 | 63 | 17.6400 | |
23 | 71 | 14.4400 | |
24 | 73 | 33.6400 | |
25 | 51 | 262.4400 | |
26 | 69 | 3.2400 | |
27 | 59 | 67.2400 | |
28 | 80 | 163.8400 | |
29 | 69 | 3.2400 | |
30 | 66 | 1.4400 | |
31 | 64 | 10.2400 | |
32 | 96 | 829.4400 | |
|
60 | 51.8400 | |
34 | 67 | 0.0400 | |
35 | 59 | 67.2400 | |
36 | 58 | 84.6400 | |
37 | 70 | 7.8400 | |
38 | 71 | 14.4400 | |
39 | 84 | 282.2400 | |
40 | 55 | 148.8400 | |
Sum | 2688 | 5592.4000 | |
Mean (x̄1) | 67.20 |
sample size (n1) = 40
sample mean (x̄1) = Σx1 /n1 = 2688/40 = 67.20
sample standard deviation (s1) = √Σ (x1-x̄1)2 /(n1-1) = √ 5592.4000/(40-1) = 11.9748
For Female (x2) :
sample | Female (x2) | (x2-x̄2)^2 |
1 | 78 | 5.5225 |
2 | 92 | 267.3225 |
3 | 59 | 277.2225 |
4 | 63 | 160.0225 |
5 | 54 | 468.7225 |
6 | 83 | 54.0225 |
7 | 78 | 5.5225 |
8 | 85 | 87.4225 |
9 | 87 | 128.8225 |
10 | 55 | 426.4225 |
11 | 37 | 1493.8225 |
12 | 65 | 113.4225 |
13 | 83 | 54.0225 |
14 | 77 | 1.8225 |
15 | 75 | 0.4225 |
16 | 67 | 74.8225 |
17 | 69 | 44.2225 |
18 | 78 | 5.5225 |
19 | 57 | 347.8225 |
20 | 66 | 93.1225 |
21 | 84 | 69.7225 |
22 | 82 | 40.3225 |
23 | 72 | 13.3225 |
24 | 75 | 0.4225 |
25 | 87 | 128.8225 |
26 | 90 | 205.9225 |
27 | 90 | 205.9225 |
28 | 91 | 235.6225 |
29 | 90 | 205.9225 |
30 | 91 | 235.6225 |
31 | 66 | 93.1225 |
32 | 88 | 152.5225 |
33 | 83 | 54.0225 |
34 | 77 | 1.8225 |
35 | 72 | 13.3225 |
36 | 57 | 347.8225 |
37 | 100 | 592.9225 |
38 | 73 | 7.0225 |
39 | 75 | 0.4225 |
40 | 75 | 0.4225 |
Sum | 3026 | 6715.1 |
Mean (x̄2) | 75.65 |
sample size (n2) = 40
sample mean (x̄2) = Σx2 /n2 =3026/40 = 75.65
sample standard deviation (s2) = √ Σ (x2-x̄2)2 /(n2-1) = √ 6715.1/(40-1) = 13.1218
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