Refer to the accompanying data set and construct a 95% confidence interval estimate of the mean pulse rate of adult females; then do the same for adult males. Compare the results.Click the icon to view the pulse rates for adult females and adult males.Construct a 95% confidence interval of the mean pulse rate for adult females.bpm<μ<bpm(Round to one decimal place as needed.)Construct a 95% confidence interval of the mean pulse rate for adult males.bpm <μ< bpm(Round to one decimal place as needed.)Compare the results.OA. The confidence intervals overlap, so it appears that adult males have a higher mean puOB. The confidence intervals do not overlap, so it appears that adult females have a higherOC. The confidence intervals overlap, so it appears that there is no difference in mean pulseO D. The confidence intervals do not overlap, so it appears that there is no difference in meaPulse Rates8473476252615478496070576578846764974085Pulse Rates (beats per minute)Males7362747055635681756266955968596168708356PrintFemales77925765567977878756346882757662657762628682677685929088889668898579765798737777DoneD- X

The data for the pulse rate of males and females are given.

Answered: Refer to the accompanying data set and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Answer using the 4-step solution.
A quantitative data set has size 50. At least how many observations lie within three standard deviations to either side of the mean?
Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 34 and the age of the winner for best actress was 43. For all best actors, the mean age is 42.5 years and the standard deviation is 6.2 years. For all best actresses, the mean age is 31.9 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Question content area bottom Part 1 Since the z score for the actor is z=enter your response here and the z score for the actress is z=enter your response here, the ▼ actress actor had the more extreme age. (Round to two decimal places.)
Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 33 and the age of the winner for best actress was 47. For all best actors, the mean age is 44.4 years and the standard deviation is 6.5 years. For all best actresses, the mean age is 32.8 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z = the V had the more extreme age. (Round to two decimal places.)
Beth scored 88 on a nutrition test. The class mean was 81 and the standard deviation was 3.2. What is Beth's T-score? Group of answer choices 47.8 71.9 22.4 Beth's T-score cannot be calculated. Not enough information is provided.
The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence interval for the mean weight of newborn elephant calves. Fifty newborn elephants are weighted. The sample mean is 244 pounds. The sample deviation is 11 pounds. State the distribution needed. Explain your reasoning. SE
Psychology students in the Izmir University of Economics completed the Dental Anxiety Scale questionnaire in 2020. In this study, scores on the scale range from 0 (no anxiety) to 20 (extreme anxiety). The mean score was 14 and the standard deviation was 3.5. Assume that the distribution of all scores on the Dental Aroxiety Scale is normal with u= 14 and g=35. Complete parts a through c A Click here to view a table of areas under the standardized normal curve O Table of Normal Curve Areas a. Suppose you score a 18 on the Dental Anxiety Scale. Find the z-value for this score. z= (Round to the nearest hundredth as needed ) b. Find the probability that someone scores between 13 and 18 on the Dental Anxiety Scale P(13sxs 18) =D (Round to four decimal places as needed) c. Find the probability that someone scores above 17 on the Dental Anxiety Scale P(x> 17)=(Round to four decimal places as needed.) Enter your answer in each of the answer boxes. |8 目國 100 |8 案 |8 業可 0 | 会效到商同我目 |
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Apply Chebyshev’s rule to solve Exercises. A quantitative data set has size 40. At least how many observations lie within two standard deviations to either side of the mean?
Use the range rule of thumb to identify the values that are significantly low, the values that are signficantly high, and the values that are neither significantly low nor significantly high. A test is used to assess readiness for college. In a recent year, the mean test score was 19.8 and the standard deviation was 5.4, Identify the test scores that are significantly low or significantly high. What test scores are significantly low? Select the correct answer below and fill in the answer box(es) to complete your choice. O A. Test scores that are between (Round to one decimal place as needed. Use ascending order.) and Get more help - Next all 9:26 PM 47°F Clear 3/27/2022 近

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 28 and the age of the winner for best actress was 44. For all best actors, the mean age is 42.3 years and the standard deviation is 8.4 years. For all best actresses, the mean age is 33.3 years and the standard deviation is 10.7 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z = and the z score for the actress is z=, the had the more extreme age. (Round to two decimal places.)

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