**Diffusion of Carbon Tetrachloride (CCl₄) Through Benzene (C₆H₆)**Carbon tetrachloride (CCl₄) diffuses through benzene (C₆H₆) as illustrated in the drawing. The concentration of CCl₄ at the left end of the tube is maintained at \(1.85 \times 10^{-2} \, \text{kg/m}^3\), and the diffusion constant is \(22.3 \times 10^{-10} \, \text{m}^2/\text{s}\). The CCl₄ enters the tube at a mass rate of \(4.29 \times 10^{-13} \, \text{kg/s}\).**Problem Statement:**Using these data and those shown in the drawing, find:(a) The mass of CCl₄ per second that passes point A.(b) The concentration of CCl₄ at point A.**Diagram Explanation:**- The diagram shows a cylindrical tube with a red section representing CCl₄ entering the tube.- A black arrow points to point A within the tube.- The distance from the entry point of CCl₄ to point A is \(5.00 \times 10^{-3} \, \text{m}\).- The tube has a cross-sectional area of \(3.00 \times 10^{-4} \, \text{m}^2\).This setup is designed to study the diffusion rate of CCl₄ through the benzene medium under the given conditions.

Cross sectional area A = 3×10-4 m2 CL = 1.85×10-2 kg/ m3 Mass flow rate m/t = 4.29×10-13 kg/s…

Answered: Carbon tetrachloride (CC14) is…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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