Carbon monoxide (CO) is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does oxygen (O₂), as indicated by these approximate standard free-energy changes in blood: reaction A: Hb + O2 →HbO₂, AG-70 kJ/mol ▼ Part A reaction B: Hb+ CO Estimate the equilibrium constant K at 298 K for the equilibrium Express your answer numerically using one significant figure. View Available Hint(s) VE ΑΣΦΑ K = ? HbCO, AG = -80 kJ/mol HbOg+CO , HbCO+O,

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+ Carbon Monoxide Poisoning
▼
Part A
Carbon monoxide (CO) is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does oxygen (O₂), as indicated by these approximate standard free-energy changes in blood:
Hb + O₂
reaction A:
→ HBO2,
AG = -70 kJ/mol
reaction B:
Estimate the equilibrium constant Kat 298 K for the equilibrium
Express your answer numerically using one significant figure.
► View Available Hint(s)
Η ΑΣΦ
K=
?
Hb+ CO → HÚCO,
AG = -80 kJ/mol
<
HbO2+CO=HbCO+O2
21 of 23
Review | Constants | Periodic Table
>
Transcribed Image Text:+ Carbon Monoxide Poisoning ▼ Part A Carbon monoxide (CO) is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does oxygen (O₂), as indicated by these approximate standard free-energy changes in blood: Hb + O₂ reaction A: → HBO2, AG = -70 kJ/mol reaction B: Estimate the equilibrium constant Kat 298 K for the equilibrium Express your answer numerically using one significant figure. ► View Available Hint(s) Η ΑΣΦ K= ? Hb+ CO → HÚCO, AG = -80 kJ/mol < HbO2+CO=HbCO+O2 21 of 23 Review | Constants | Periodic Table >
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