Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S, (g) + C(s) = CS,(g) Ke = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 16.6 mol S, (g) with excess carbon in a 6.90 L reaction vessel held at 900 K until equilibrium is attained? g mass of CS, (g):
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S, (g) + C(s) = CS,(g) Ke = 9.40 at 900 K How many grams of CS, (g) can be prepared by heating 16.6 mol S, (g) with excess carbon in a 6.90 L reaction vessel held at 900 K until equilibrium is attained? g mass of CS, (g):
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:General Chemistry 4th Edition
McQuarrie Rock Gallogly
University Science Books
presented by Macmillan Learning
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
S,(g) + C(s) = CS, (g)
= 9.40 at 900K
Ko
How many grams of CS, (g) can be prepared by heating 16.6 mol S,(g) with excess carbon in a 6.90 L reaction vessel held
2,
at 900 K until equilibrium is attained?
mass of CS,(g):
Question Source: MRG - General Chemistry Publis
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