At 525 oC, Keq = 0.387 for the reaction: 1/3 NO2(g) + 1/3 N2O(g) NO(g)(a) What is the value of Keq for the reaction NO(g) 1/3 NO2(g) + 1/3 N2O(g)?Keq =_______ .(b) What is the value of Keq for the reaction NO2(g) + N2O(g) 3 NO(g)?Keq = _________ .(c) What is the value of Keq for the reaction 3 NO(g) NO2(g) + N2O(g)?Keq = ________ .

Answered: At 525 oC, Keq = 0.387 for the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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At 525 ^oC, K_eq = 0.387 for the reaction:

1/3 NO₂(g) + 1/3 N₂O(g) NO(g)

(a) What is the value of K_eq for the reaction NO(g)  1/3 NO₂(g) + 1/3 N₂O(g)?

K_eq =_______ .

(b) What is the value of K_eq for the reaction NO₂(g) + N₂O(g)  3 NO(g)?

K_eq = _________ .

(c) What is the value of K_eq for the reaction 3 NO(g)  NO₂(g) + N₂O(g)?

K_eq = ________ .

Expert Solution

Step 1

The value of the reaction quotient at equilibrium is known as the equilibrium constant for a reaction. For the given reaction the equilibrium constant is written as follows:

$1 / 3 {NO}_{2} (g) + 1 / 3 N_{2} O (g) ⇌ NO (g) K_{eq} = \frac{[NO]}{{[{NO}_{2}]}^{1 / 3} {[N_{2} O]}^{1 / 3}} = 0.387$

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