A proton moving at 2.5 E6 m/sec at 25 degrees east of north enters a uniform magnetic field of 1550 T East. Determine the direction of the instantaneous acceleration and the radius of curvature of its new circular path.
A proton moving at 2.5 E6 m/sec at 25 degrees east of north enters a uniform magnetic field of 1550 T East. Determine the direction of the instantaneous acceleration and the radius of curvature of its new circular path.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
Problem 1P: A proton travels with a speed of 3.00 106 m/s at an angle of 37.0 with the direction of a magnetic...
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A proton moving at 2.5 E6 m/sec at 25 degrees east of north enters a uniform magnetic field of 1550 T East. Determine the direction of the instantaneous acceleration and the radius of curvature of its new circular path.
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Can you solve this problem with the equation Fb = q x v x B x sin ( theta ) and on this problem theta is given at 25 degrees.
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