A length L of straight, horizontal wire is oriented perpendicular to a uniform horizontal magnetic field B. What current I must flow through the wire for the net force on the wire (magnetic p
Q: A proton moves through a uniform electric field given by vector E = 50.0 j hat V/m and a uniform…
A:
Q: In the figure below, the current in the long, straight wire is lj=17.1 A, and the wire lies in the…
A:
Q: The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the…
A: We know that the formula of the magnetic field is given as FB= qvBsinθ where q is the charge v is…
Q: A long straight horizontal wire carries a current I= 1.80 A to the left. A positive 1.00 C charge…
A:
Q: A long, straight wire carries a current of 5.20 A. An electron is traveling in the vicinity of the…
A:
Q: Consider the same situation as in the previous problem. This time the magnet has mass 4.88 kg and…
A: Magnet of mass m = 4.88 kg Pulling force on magnet F = 178.2 N. Tension force in the cord T = ?
Q: A particle with positive charge q = 3.68 x 10-18 C moves with a velocity v = (51 + 5ĵ- k) m/s…
A:
Q: Three long, straight wires are seen end-on as shown in the figure. The distance between the wires is…
A:
Q: A particle with a charge of 5.75 µC and a speed of 351 m/s is acted on by both an electric and a…
A: Determine the electric force.
Q: A particle with charge q and speed v enters a magnetic field of strength B, moving in a plane…
A:
Q: A proton is traveling with a velocity of v = vxî + vy j, where vx = 54 m/s and vy = 62 m/s. The…
A: The objective of the question is to find the magnitude of the force experienced by a proton moving…
Q: An experimental magnetically levitated train is supported by magnetic repulsion forces exerted in a…
A: The magnetic force on a current-carrying conductor placed in the magnetic field is directly…
Q: A proton and an alpha particle are moving perpendicular to a uniform magnetic field with the same…
A:
Q: 5. A particle of charge q = 0.200 C and mass m 2.00 kg is moving with instantaneous velocity v =…
A:
Q: A magnetic field of 0.2 T is acting in the south-west direction. (You can ignore the earth’s…
A: Given Data: Magnetic field (B) = 0.2 T.Mass of the particle (m) = 0.06 kg.Charge on the particle (q)…
Q: Suppose a 8.08mC charge moves with velocity 112.2 m/s perpendicular to a region of space where a…
A:
Q: Two particles have the same charge (q1=q2=1.6x10-19C) and different masses undergo circular motion…
A:
Q: A proton (with mass mp = 1.67 x 10-27 kg, charge qp = 1.6 x 10-19 C) moving with a speed of 0.80 x…
A: Ans:- Image-1
Q: The electric force on a proton. In a magnetic field of 200 i G, a proton moves with a speed equal to…
A: See below
Q: A positively charged particle, q, of mass m moves at a constant velocity along the x direction. The…
A: Drag Force: This force is exerted by the fluid on the object traveling through it and it opposes its…
Q: A 19.4 cm × 30.5 cm rectangular loop of wire carries 1.00 A of current clockwise around the loop.…
A:
Q: What is the direction of the magnetic force on current 2 (by the magnetic field of current 1)?…
A: Given data: Two wires having currents in opposite directions Direction of current in wire 1 is…
Q: In New England, the horizontal component of the earth's magnetic field has a magnitude of 1 . 6 × 10…
A: Given data: Magnetic field (B) = 1.6 × 10-5 T Velocity (v) = 2.1 × 106 m/s Direction of velocity is…
Q: Since a magnetic field exert forces on moving charges, it exerts a force on current carrying wires.…
A: Given- Magnetic field (B) = 0.5 T Current (I) = 1.2 A As the magnetic field is pointing out of the…
Q: The magnetic force dFB on a infinitesimal segment of current I is dF, = 1 dī × B Where dL is the…
A: The magnetic force is given by the formuladFb=IdL×BHere, I is the current passing through the…
Q: A 1.6 m long straight horizontal wire carrying a current of 5.3 A along the +x-direction is in a…
A:
Q: At time t1, an electron is sent along the positive direction of an x axis, through both an electric…
A: Given Velocity Vs = 110 m/s Electric field = E→ Magnetic field = B→ Time =…
Q: A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 4.15…
A: We know that force on acharge particle moving with speed v in magnetic field is given by F=qvBsinθ…
A length L of straight, horizontal wire is oriented perpendicular to a uniform horizontal magnetic field B. What current I must flow through the wire for the net force on the wire (magnetic plus gravitational) to be zero? Assume L = 2.0 m, B = 1.5 T into the page, the mass of the wire is m = 0.50 kg, and .g = 9.8 m/s2.
6.5 A, to the right
1.6 A, to the right
3.3 A, to the right
3.3 A, to the left
6.5 A, to the left
1.6 A, to the left
Step by step
Solved in 2 steps with 1 images
- A straight, vertical wire carries a current of 2.15 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has a magnitude of B = 0.554 T and is horizontal. What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is south? Express your answer with the appropriate units. F: 1 O μA Value Submit Request Answer Units 5994 ?An iron bolt of mass 58.5 g hangs from a string 37.5 cm long. The top end of the string is fixed. Without touching it, a magnet attracts the bolt so that it remains stationary, but is displaced horizontally 25.0 cm to the right from the previously vertical line of the string. Draw a free-body diagram of the bolt. Find the tension in the string. Find the magnetic force on the bolt. magnitude directionA magnetic field can force a charged particle to move in a circular path. Suppose that an electron moving in a circle experiences a radial acceleration of magnitude 3.0 × 1014 m/s2 in a particular magnetic field. (a) What is the speed of the electron if the radius of its circular path is 0.14 m? (b) What is the period of the motion?
- The magnetic force dFg on a infinitesimal segment of current I is dFs = I dEx B Where di is the displacement vector of the infinitesimal current segment. The total magnetic force on a finite current segment is F = 1J (dL x B) 1. If the magnetic field is uniform in space the magnetic force on current simplifies to FB = {(x5). What is vector in this expression? Choose one. is the length of the current segment is the vector from the point where the current enters the uniform field to the point where the current leaves the uniform field. a. What is the magnetic force on the portions of the wire to the left of the dashed line? • is the current. 2. The magnetic field is zero to the left of the dashed line. The magnetic field to the right of the dashed line is uniform outwards. A current carrying wire goes through the region as shown. b. What is the magnetic force on the bottom wire segment? Write answer in component vector form. c. What is the magnetic force on the slanted wire segment?…As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will travel in a circular path. If the magnitude of the magnetic field is 0.170 T, the speed of the particle is 12.0 x 10° m/s, the radius of the trajectory of the path is 105.5 cm, and the charge has a magnitude of 3.20 x 1019 C, determine the following. B (a) sign of the charged particle O positive O negative (b) mass of the particle (use the conversion 1 u = 1.66 x 10-27 kg)Q1/ A proton moving at 4.00 × 10“ m/s through a magnetic field of magnitude 1.70 T experiences a magnetic force of magnitude 8.20 × 10 N. What is the angle between the proton's velocity and the field?
- The National High Magnetic Field Laboratory once held the world record for creating the strongest magnetic field. For brief periods of time, their largest multi-shot pulsed magnet can produce magnetic fields in excess of 85 T. To see if such a strong magnetic field could pose health risks for nearby workers, calculate the maximum acceleration amax the field could produce for Nat ions (of mass 3.8 x 10-26 kg) in blood traveling through the aorta. The speed of blood is highly variable, but 45 cm/s is reasonable in the aorta. m/s? Amax =Two long, parallel wires are separated by 2.61 cm and carry currents of 2.61 A and 4.55 A, respectively. Find the magnitude of the magnetic force F that acts on a 3.45 m length of either wire. N F =In New England, the horizontal component of the Earth's magnetic field has a magnitude of 1.9 × 10-5 T. An electron is shot vertically straight up from the ground with a speed of 3.3 × 106 m/s. What is the magnitude of the acceleration caused by the magnetic force? Ignore the gravitational force acting on the electron.
- An electron beam is directed horizontally into a region where there is both an electric field and a magnetic field. The electric field points upward with a magnitude EE = 2.9 N/C, as shown in the figure. While moving through the region, the electron beam remains directed in a straight, horizontal line with a speed of 460 m/s. 1.) Express the magnitude of the electric force using the electric field E and the elementary charge e. 2.) Calculate the numerical value of the magnitude of the electric force in newtons. 3.) Express the magnitude of the magnetic force in terms of the elementary charge ee, electron speed vv, and BB, the magnitude of the magnetic field. 4.) If the electron is continuing in a horizontal straight line, express the magnitude of the magnetic field in terms of vv and EE, B = ? 5.) Calculate the magnitude of the magnetic field in tesla, if the electron continues in a horizontal straight line. 5.)A negative charge of q = -2.2 * 10-17 C and m = 2.3 * 10-26 kg enters a magnetic field B = 1.9 T with initial velocity v = 270 m/s as shown in the attached image. The magnetic field points into the screen. Express the radius R, of the circular motion in terms of the centripetal acceleration a and the speed v. Calculate the numerical value of the radius R in meters.A charge of 1.2 C having an initial velocity of = 3.91+3.3 m/s enters a region with an electric field È = 3.1î N/C and a magnetic field B = 3.71+4.2k T. Calculate the magnitude of the force on the charge immediately after it enters the region. Express your answer in Newtons (write just the value, not the unit), rounding to one digit after the decimal separator. Add your answer Continue