Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hello, Im trying to perform a grignard reaction, not sure I'm doing it correctly. Can someone show me how to turn the MgBr substituent into a double bond with arrows so I understand how it happens exactly please.
![### Image Transcription for Educational Website
**Step 1: Formation of Grignard Reagent**
- **Reactant:** Bromobenzene derivative with a bromine atom (Br) attached to a benzene ring and an alkyl chain.
- **Reagent:** Magnesium (Mg).
- **Product:** Grignard reagent, where the bromine atom is replaced by MgBr, forming an organomagnesium compound attached to the alkyl-benzene structure.
**Chemical Reaction:**
\[
\text{C}_6\text{H}_5\text{Br-R} + \text{Mg} \rightarrow \text{C}_6\text{H}_5\text{MgBr-R}
\]
**Step 2: Reaction of Grignard Reagent**
- **Reactant:** Grignard reagent from Step 1.
- **Reagent:** Unspecified, indicated by a question mark (?).
- **Product:** A benzene derivative with an alkene group attached, indicating a possible reaction with a suitable electrophile or other reagent to form a new double bond.
**Chemical Reaction:**
\[
\text{C}_6\text{H}_5\text{MgBr-R} + \,? \, \rightarrow \text{C}_6\text{H}_5-\text{CH}= \text{CH-R}
\]
**Explanation:**
- **Grignard Reagent Formation:** Grignard reagents are typically formed by the reaction of an alkyl or aryl halide with magnesium in an ether solvent. They are highly reactive and often used in the formation of carbon-carbon bonds.
- **Second Step: Product Formation:** The exact reagent needed for the second step is unspecified in the image. Typically, Grignard reagents can react with various electrophiles, including ketones, aldehydes, and esters, to form alcohols. However, in this case, the final product is an alkene, suggesting an elimination or coupling reaction might be involved.
**Note:** Always handle Grignard reagents with care and under appropriate conditions, as they are moisture-sensitive and highly reactive.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7588948d-a8a4-4b5d-b85a-786e24f76953%2F4f35bade-9e3d-4c10-a803-b71f18fec18c%2Fpw06345j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Image Transcription for Educational Website
**Step 1: Formation of Grignard Reagent**
- **Reactant:** Bromobenzene derivative with a bromine atom (Br) attached to a benzene ring and an alkyl chain.
- **Reagent:** Magnesium (Mg).
- **Product:** Grignard reagent, where the bromine atom is replaced by MgBr, forming an organomagnesium compound attached to the alkyl-benzene structure.
**Chemical Reaction:**
\[
\text{C}_6\text{H}_5\text{Br-R} + \text{Mg} \rightarrow \text{C}_6\text{H}_5\text{MgBr-R}
\]
**Step 2: Reaction of Grignard Reagent**
- **Reactant:** Grignard reagent from Step 1.
- **Reagent:** Unspecified, indicated by a question mark (?).
- **Product:** A benzene derivative with an alkene group attached, indicating a possible reaction with a suitable electrophile or other reagent to form a new double bond.
**Chemical Reaction:**
\[
\text{C}_6\text{H}_5\text{MgBr-R} + \,? \, \rightarrow \text{C}_6\text{H}_5-\text{CH}= \text{CH-R}
\]
**Explanation:**
- **Grignard Reagent Formation:** Grignard reagents are typically formed by the reaction of an alkyl or aryl halide with magnesium in an ether solvent. They are highly reactive and often used in the formation of carbon-carbon bonds.
- **Second Step: Product Formation:** The exact reagent needed for the second step is unspecified in the image. Typically, Grignard reagents can react with various electrophiles, including ketones, aldehydes, and esters, to form alcohols. However, in this case, the final product is an alkene, suggesting an elimination or coupling reaction might be involved.
**Note:** Always handle Grignard reagents with care and under appropriate conditions, as they are moisture-sensitive and highly reactive.
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can you show all the mechanism arrows please? Im not sure how to correctly take the OMgBr off , and how the OH turned into a double bond
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