Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you help me with the number 2 questions? Also can you please show the step-by-step including the formula?
Transcribed Image Text:Calculations for Temperature and Phase Change Worksheet
The heat of fusion of ice is 79.7 cal/g.
The heat of vaporization of water is 540 cal/g.
Report the answer using the correct number of significant figures!
1. How much energy is required to melt 100.0 grams of ice? Mass of ice = 100.0g
Heat of fusion of ice: 79.
100.0g|79.7.cal-1970 cal
2. How much energy is required to vaporize 234.5 g of water?
234.5g 540 cal-
-
1.224
1.2 cal/g
12 6630 1.2663X105
1.3x105
Answer: 1.3 x 105 cal
cal
3. If 30.6 calories are required to vaporize 25 g of a substance, what is the heat of vaporization of
that substance?
mass of substance: 25g
energy require vaporization: 30.6 Cal
may
30.6 cal
259
26.00 °C?
100c,05 (6બ (22)=xtel
3.00x 10³cal
4. How much energy is removed from 500.0 g of water when the temperature is lowered by 1.10 °C?
mass m) = 500.09
AT=-1.10°C
500.0g (ca.1000) = [
500.g (4.1845 -1.10 23.01.2-2,3012×10³.
-550 cal
5. How much energy is required to raise the temperature of 1000.0 g of water from 23.00 °C to
0.0924 cal
3-21) (100.024)
до с
m= 1000.09 Q=SOMIAT
S=1 cal/goc Teinal-Tinitid
T₁ = 23.00%
T2=26.00°C
3.00 x 10³ cal (or 1.26 x 10¹J)
is required to raise the
mass of copper: 100g
Specific heat copper: 0.0924cal/g °C
AT=100.0°C
Answer: 92.4 cal
7. If 25.6 J of energy raised 786 g of a substance from 20.0°C to 35.0°C, what is the specific heat of
the substance (S)?
= mxsx Delta + mass(m) = 786 gram
T₁ = 20.0%
T₂=35:0°C
-0.002171332 TFinal-Tinitial
0.00217
4184511.2552x10
Içal
6. The specific heat of copper is (0.0924 cal/g°C), how much energy
temperature of 10.0 g of copper by 100.0 °C?
10.09
Mass of water 234.59
Heat of vaporization: 540 cal/g
Heat of vaporization substance: 1.2 cal/g
Answer: 1.2 cal/g
25.65=786 gx sx35°C-20°c)
---5=25.6J
7869x
:79.7 cal/g
Answer: 7970 cal
15°C
Q==ssocal
Answer: -550. cal (or -2.30 x 10³ J)
92.4call
(2617X10³J/g °C
26.00-23.00=3%
Answer: 2.17 x 10-³J/g °C
35.0%-2010°C = 15.0°C
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