Calsulate specific heat Dissolution ofNaOHกงงMass of water in cupFinal temp. of water + NaOHInitial temp. of waterAT WaterAH Dissolution NaOH -"CaicuraORT.AH (NaOH)=-AH(30g (water)29.0°C210°C8°C(82) 100 3..=1003.20Conjos

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Answered: Calsulate specific heat Dissolution of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Gas Pressure Conversions • A given P(atm) takes different column heights (h) of different liquids (p) to balance in a barometer: P(H,0) = p(H,O) gn h(H,0) P(atm) = p(Hg) g, h(Hg) 1 h oc %3D %3D ... Find mm(H,0) that measures 1 atm = 760 mmHg: %3D h(H,O) = h(Hg) x e(Ha= 760 mm(Hg) x 13.5_g/mL = [O,2le0 mm(H,O) %D %3D p(H2O) 1.0 g/mL A barometer with liquid twice as dense as water shows 1 atm as: 0.38 m 1.52 m 5.15 m 20.6 m Convert 3.11 x 10-5 atm into mTorr 1 atm =100 Torr 3.11 x 10-5 atm xloO Torr 1 atm 1 mTorr 10-3 Torr 23.0mTorr (AKA: µ) 1 in(Hg) = 25.t mm(Hg) Pa = 29.92 inHg 80.6 KPa Convert 23.8 inHg into kPa %3D 1 atm = 760 mmHg = (01325 25.4 mm(Hg)x 1 in(Hg) %3D 101325 Pa 760 mmHg 1o Pa 23.8 inHg x x 1 kPa =
The volume of HCI is 100 mL , mass of solid added is 1.008g, moles of solid 0.0276 Mol, mass of HCI is 100g, initial temperature is 21.8 degrees Celsius, Final temperature is 30.7 degrees Celsius, Calculate q rxn(= -mc Delta T of HCI),
Mail- Thomps 3 3 https://app.101edu.co 80 P Parchment Reg F3 $ 4 Write the balanced NET ionic equation for the reaction when AlCl3 and NaOH are mixed in aqueous solution. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction. 1 2 + 04- F4 Na set TW6D2PHI.pdf 2 % ( ) 5 3 4 03 □ F5 Unofficial Transcri 4 Question 15 of 40 ↑ NR O 6 5 05 0+ F6 6 UAFS Registra Graduation Applica MacBook Air & 7 2 2+ (s) (1) CI Al 7 8 9 0 09 口。 3+ 7 04+ F7 8 (g) (aq) • x H₂O 8 DII F8 H My UAFS-St Delete DD F9 M 0
A mixture combining 60 mL ethanol (C₂H6O) with 75 mL water (H₂O) is prepared at 280 K. The partial molar volumes of ethanol (E) and water (W) when mixed in these proportions (right column below) and in pure form (left column below) are ethanol water pure substance molar volume 58.2 mL/mol 18.00 mL/mol partial molar volume 55.3 mL/mol 17.7 mL/mol Determine the volume of the ethanol-water mixture. [Hint: You will need to determine the moles of each component.]
°F rtly cloudy m/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-lvWyv8WYLP6W0cqJcWJdIACROQwyw24GWHInMM72ts 1 NTBcSzwZOGGhrmIP4yCejeRhX9HIzqlzRTj2iaDBXTCRIHYWNO_-o?10... O CHEMICAL REACTIONS Calculating molarity using solute moles A chemist prepares a solution of mercury(II) iodide (HgI₂) by measuring out 0.0161 μmol of mercury(II) iodide into a 300. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in μmol/L of the chemist's mercury(II) iodide solution. Round your answer to 3 significant digits. µ mol L Explanation Check x10 X Ś Q Search 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use **************** D 1/5 www Jessi Privacy Center | Accessibility
A mixture of phenol and water, under certain conditions of temperature and composition, forms two separate liquid phases, one rich in phenol and the other rich in water. At 30⁰ the compositions of the upper and lower layers are 70% and 9% by mass phenol, respectively. If 40kg of phenol and 60kg of water are mixed and the layers are allowed to separate at 30⁰C, what will be the weight of the two layers?
The proximate analysis (% air dried basis), the ultimate analysis (% d.m.m.f basis) and experimental gross calorific value (kcal/kg on air dried basis) is as follows: Proximate Ultimate analysis C.V. analysis % % Kcal/kg M VM А FC C HONS (exp. Value) 29 16 53 86 6 5 217200 Calculate its gross calorific value and net calorific value using (i) Goutal & (ii) Mazumdar correlations.
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volume reactants gas products Na₂CO3 (s) + 2 HCI (aq) solution mass separate layer gram liquid solid coefficient CO₂ (g) + H₂O (1) + 2 NaCl (aq)|
•0= AG° + RT * In (K) %3D • -AG° = RT * In (K) %3D • AG° = -RT * In (K) %3D AG° = -0.616 * In (K)... %3D
5. (69,85) A 25g ice cube (pure water) at -10°C is placed into a 115g sample of pure water at 25°C. The information for water is given below. Determine the final temperature, in °C, of the water. You must consider all applicable cooling/heating/phase change steps for both the ice cube and the water. Cs(solid) = 2.1 Jg¬'K-1 Cs (liquid) = 4.2 Jg-K-1 AHfus = 6.0 kJ mol-1 %3D

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Calsulate specific heat Dissolution of NaOH ก ง ง Mass of water in cup Final temp. of water + NaOH Initial temp. of water AT Water AH Dissolution NaOH - "CaicuraORT. AH (NaOH)=-AH( 30g (water) 29.0°C 210°C 8°C (82) 100 3.. =1003.20 Conjos