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Calorimeter mass  162.2 g Mass of calorimeter + cold water 226.6 g Initial temperature of cold water 22°C Temperature of hot water before mixing 85°C Final temperature of the mixture 46°C Mass of calorimeter + mixture 302.7 g Specific heat of water = 1cal/ g °C 15- Heat absorbed by cold water = q = mass of cold water x 1 cal /g ° C X ∆T cold H2O = ___________________ 16- Heat given up by hot water= q = Mass of hot water x 1 cal /g ° C X ∆T H2O hot = _________________________ 17- Heat of the calorimeter q system = q hot water + q cold water + q calorimeter Q system = 0 (isolated system) qcalorimeter = - (q hot water + q cold water)

Calorimeter mass  162.2 g Mass of calorimeter + cold water 226.6 g Initial temperature of cold water 22°C Temperature of hot water before mixing 85°C Final temperature of the mixture 46°C Mass of calorimeter + mixture 302.7 g Specific heat of water = 1cal/ g °C 15- Heat absorbed by cold water = q = mass of cold water x 1 cal /g ° C X ∆T cold H2O = ___________________ 16- Heat given up by hot water= q = Mass of hot water x 1 cal /g ° C X ∆T H2O hot = _________________________ 17- Heat of the calorimeter q system = q hot water + q cold water + q calorimeter Q system = 0 (isolated system) qcalorimeter = - (q hot water + q cold water)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calorimeter mass  162.2 g
Mass of calorimeter + cold water 226.6 g
Initial temperature of cold water 22°C
Temperature of hot water before mixing 85°C
Final temperature of the mixture 46°C
Mass of calorimeter + mixture 302.7 g

Specific heat of water = 1cal/ g °C
15- Heat absorbed by cold water = q = mass of cold water x 1 cal /g ° C X ∆T cold H2O = ___________________
16- Heat given up by hot water= q = Mass of hot water x 1 cal /g ° C X ∆T H2O hot = _________________________
17- Heat of the calorimeter q system = q hot water + q cold water + q calorimeter
Q system = 0 (isolated system)
qcalorimeter = - (q hot water + q cold water)
18- qcalorimeter = mCp ∆T °C
Calorimeter heat capacity (Cc)= mCp = Cc = q calorimeter / ∆T C

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