The temperature of a sample of silver increased by 23.4 °C when 273 J of heat was applied. Substance Specific heat J/(g • °C) lead 0.128 What is the mass of the sample? silver 0.235 сорper 0.385 iron 0.449 aluminum 0.903 m = g
The temperature of a sample of silver increased by 23.4 °C when 273 J of heat was applied. Substance Specific heat J/(g • °C) lead 0.128 What is the mass of the sample? silver 0.235 сорper 0.385 iron 0.449 aluminum 0.903 m = g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
The temperature of a sample of silver increased by 23.4 °C when 273 J of heat was applied. What is the mass of the sample?
*m* = [______] g
**Table of Specific Heats:**
| Substance | Specific heat J/(g·°C) |
|-----------|-------------------------|
| Lead | 0.128 |
| Silver | 0.235 |
| Copper | 0.385 |
| Iron | 0.449 |
| Aluminum | 0.903 |
**Explanation of the Table:**
The table provides specific heat capacities for different substances. Specific heat is a measure of the amount of heat required to change the temperature of one gram of a substance by one degree Celsius. Here, different metals like lead, silver, copper, iron, and aluminum are listed with their respective specific heat values in J/(g·°C).
To solve the problem, use the formula:
\[ Q = m \times c \times \Delta T \]
Where:
- \( Q \) is the heat applied (273 J),
- \( m \) is the mass (unknown),
- \( c \) is the specific heat of silver (0.235 J/(g·°C)),
- \( \Delta T \) is the change in temperature (23.4 °C).
Rearranging the formula to solve for \( m \):
\[ m = \frac{Q}{c \times \Delta T} \]
Substitute the given values to find the mass of the sample.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cab08ae-8e5c-4fa2-a89b-725536e38ab3%2F3e29e4f1-0ca6-43d0-bedb-f85c5e4def8e%2Fore0idp_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
The temperature of a sample of silver increased by 23.4 °C when 273 J of heat was applied. What is the mass of the sample?
*m* = [______] g
**Table of Specific Heats:**
| Substance | Specific heat J/(g·°C) |
|-----------|-------------------------|
| Lead | 0.128 |
| Silver | 0.235 |
| Copper | 0.385 |
| Iron | 0.449 |
| Aluminum | 0.903 |
**Explanation of the Table:**
The table provides specific heat capacities for different substances. Specific heat is a measure of the amount of heat required to change the temperature of one gram of a substance by one degree Celsius. Here, different metals like lead, silver, copper, iron, and aluminum are listed with their respective specific heat values in J/(g·°C).
To solve the problem, use the formula:
\[ Q = m \times c \times \Delta T \]
Where:
- \( Q \) is the heat applied (273 J),
- \( m \) is the mass (unknown),
- \( c \) is the specific heat of silver (0.235 J/(g·°C)),
- \( \Delta T \) is the change in temperature (23.4 °C).
Rearranging the formula to solve for \( m \):
\[ m = \frac{Q}{c \times \Delta T} \]
Substitute the given values to find the mass of the sample.
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