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Calculations. 1. Standard solutions and Beer's law calibration curve (1) Mass of SA Molar mass of salicylic acid (SA), HOC6H4COOH (2) Moles SA = mass/molar mass 0,165 138.1 0,500 = (0.500/10.0)x(stock solution concentration)/o. O 0.100 (3) Concentration of SA stock solution = mol/0.100L = (2)/0.100= SA solution "4" (0.400 mL stock to 10.0 mL) = 0.165 8 The SA is hydrolyzed and quantitatively transferred to a 100. mL volumetric flask, so: 1.1947/07 SA solution "3" (0.300 mL stock to 10.0 mL) = 138.1 (4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL) 33 x 2762 SA solution "2" (0.200 mL stock to 10.0 mL) SA solution "1" (0.100 mL stock to 10.0 mL) -1.1947 mol SA x10 g/mol 2762 -3 33 mol/L mol/L As-0-888 mol/L A+ = -695 mol/L A= 0.422 A₂ = 0.35 mol/L mol/L A₁ = 0. r these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach calibration curve with this report.

Calculations. 1. Standard solutions and Beer's law calibration curve (1) Mass of SA Molar mass of salicylic acid (SA), HOC6H4COOH (2) Moles SA = mass/molar mass 0,165 138.1 0,500 = (0.500/10.0)x(stock solution concentration)/o. O 0.100 (3) Concentration of SA stock solution = mol/0.100L = (2)/0.100= SA solution "4" (0.400 mL stock to 10.0 mL) = 0.165 8 The SA is hydrolyzed and quantitatively transferred to a 100. mL volumetric flask, so: 1.1947/07 SA solution "3" (0.300 mL stock to 10.0 mL) = 138.1 (4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL) 33 x 2762 SA solution "2" (0.200 mL stock to 10.0 mL) SA solution "1" (0.100 mL stock to 10.0 mL) -1.1947 mol SA x10 g/mol 2762 -3 33 mol/L mol/L As-0-888 mol/L A+ = -695 mol/L A= 0.422 A₂ = 0.35 mol/L mol/L A₁ = 0. r these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach calibration curve with this report.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculations. 1. Standard solutions and Beer's law calibration curve (1) Mass of SA Molar mass of salicylic acid (SA), HOC6H4COOH (2) Moles SA = mass/molar mass 0,165 138.1 0,500 = (0.500/10.0)x(stock solution concentration) /o. 6 0.100 (3) Concentration of SA stock solution = mol/0.100L = (2)/0.100 = SA solution "4" (0.400 mL stock to 10.0 mL) = 0.1658 SA solution "3" (0.300 mL stock to 10.0 mL) = The SA is hydrolyzed and quantitatively transferred to a 100 mL volumetric flask, so: 11997 / 0 SA solution "2" (0.200 mL stock to 10.0 mL) (4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL) 33 x 2762 = SA solution "1" (0.100 mL stock to 10.0 mL) 138.1 -1.1947 mol SA x 10 11 g/mol 33 2762 -3 mol/L mol/L As=0-888 mol/L A+ = +695 0.422 A2 = 0.351 A₁ = 0,1 mol/L mol/L mol/L A₁ = 0. ter these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach s calibration curve with this report.
Transcribed Image Text:Calculations. 1. Standard solutions and Beer's law calibration curve (1) Mass of SA Molar mass of salicylic acid (SA), HOC6H4COOH (2) Moles SA = mass/molar mass 0,165 138.1 0,500 = (0.500/10.0)x(stock solution concentration) /o. 6 0.100 (3) Concentration of SA stock solution = mol/0.100L = (2)/0.100 = SA solution "4" (0.400 mL stock to 10.0 mL) = 0.1658 SA solution "3" (0.300 mL stock to 10.0 mL) = The SA is hydrolyzed and quantitatively transferred to a 100 mL volumetric flask, so: 11997 / 0 SA solution "2" (0.200 mL stock to 10.0 mL) (4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL) 33 x 2762 = SA solution "1" (0.100 mL stock to 10.0 mL) 138.1 -1.1947 mol SA x 10 11 g/mol 33 2762 -3 mol/L mol/L As=0-888 mol/L A+ = +695 0.422 A2 = 0.351 A₁ = 0,1 mol/L mol/L mol/L A₁ = 0. ter these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach s calibration curve with this report.
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