For this question, let's assume that both the number of moles (0.438 mol Co(No3)2 and the mass of the solute 80.1 were not given in the question. How we calculate to get both of these figures?

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For this question, let's assume that both the number of moles (0.438 mol Co(No3)2 and the mass of the solute 80.1 were not given in the question. How we calculate to get both of these figures? 

Expeniment
and
name
Chemical formula
Cobalt (11) nitzate
Co(NOs)2
Buldatance Aane and dhemical farmula
mm, q/mo!
182.95g lmol
Fruihal volume , L
Iniial concentrahion
measure d, mal/L
Number of mole's and massof
mass Of solute
500ML
0.876 mollL
0 -438 mol Colw0z
to
Concentration after eventahom
affer evapo
1.461 mal L
Can you please explatn to calculate how the
180.19) cduo wsas arrived at ?
Thanks
ass
Transcribed Image Text:Expeniment and name Chemical formula Cobalt (11) nitzate Co(NOs)2 Buldatance Aane and dhemical farmula mm, q/mo! 182.95g lmol Fruihal volume , L Iniial concentrahion measure d, mal/L Number of mole's and massof mass Of solute 500ML 0.876 mollL 0 -438 mol Colw0z to Concentration after eventahom affer evapo 1.461 mal L Can you please explatn to calculate how the 180.19) cduo wsas arrived at ? Thanks ass
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