Calculate the vapor pressure (in torr) of a solution prepared by mixing 0.542 mol of toluene (92.14 g/mol) in 0.947 mol of hexane (86.2 g/mol). P°hexane = 97.51 torr and P°tolune = 21.75 torr. Report your answer to the tenths place and do not include units.
Calculate the vapor pressure (in torr) of a solution prepared by mixing 0.542 mol of toluene (92.14 g/mol) in 0.947 mol of hexane (86.2 g/mol). P°hexane = 97.51 torr and P°tolune = 21.75 torr. Report your answer to the tenths place and do not include units.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the vapor pressure (in torr) of a solution prepared by mixing 0.542 mol of toluene (92.14 g/mol) in 0.947 mol of hexane (86.2 g/mol).
P°hexane = 97.51 torr and P°tolune = 21.75 torr. Report your answer to the tenths place and do not include units.
Expert Solution
Step 1
Raoult's law :-
The vapor pressure of a component in a liquid-liquid solution is directly proportional to mole fraction of that component in solution
P1 = P1°X1
P1 = vapor pressure of component 1 in solution
P1° = vapor pressure of pure component 1
X1 = mole fraction of component 1
Similarly for second complement
P2 = P2°X2
The total pressure of solution is given by
Ptotal = P1°X1 + P2°X2
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