Answered: Pentane (C5H12) and hexane (C6H14) form…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Pentane (C5H12) and hexane (C6H14) form an ideal solution. At 25°C the vapor pressures of pentane and hexane are 511 and 150 torr, respectively. A solution is prepared by mixing 25 mL pentane (density, 0.63 g/mL) with 45 mL hexane (density, 0.66 g/mL). What is the composition by mole fraction of pentane in the vapor that is in equilibrium with this solution?

20
BIOLOGY
1-x₂ + Pg=P (1-x₂) = 42.2 (1-0.05901 95 361) = 41.471 mmHq
Relative lowering of vapour pressure=
AP
po
-
O
pº-Ps 42.241.471 = 0.01727 = 0.0173 mmHg
po
42.2
2. Pentane (CsH₁2) and hexane (C6H₁4) form an ideal solution. At 25°C the vapor pressures of pentane and hexane
are 511 and 150. torr, respectively. A solution is prepared by mixing 25 mL pentane (density=0.63 g/mL) with 45
mL hexane (density=0.66 g/mL).
M
V=25 mL
a) What is the vapor pressure of the resulting solution?
D=M=drv
va 45 mL
D= 0.66 glml
Density
of part. 0.63 ML
=
molar mass
of C5Hz 72 g/mol
so...
.
$
15.75
15.75 72
= 0.63 g/mL x 25 mL
= 15.75 9
0.21875 moles of
C3H12
4
| mole
fraction
M= 29.79
MW = 86 g/mol
so... 29.7/86
2
= 0.3451
0.56405
0.3453 mol
of C6H4
0.21875 -= 0.38782 CSHI VP of solution =PX C₂H₂ + XPCGH14
0.56405
= Ell torr
total n=0.21875 +0.3453
n=0.56405
=(0.38782 x 5) + (0.612 17 x 150)
= 198.17602 +91.8255
- 290.00152
= 290 torr
b) What is the composition by mole fraction of pentane in the vapor that is in equilibrium with this solution?
= 0.61217 C6 M19
150 toir

Expert Solution

Step 1

(b)

Given that, vapour pressure of the pentane at 25^oC is 511 torr.

A solution is prepared by mixing 25 mL pentane (density, 0.63 g/mL) with 45 mL hexane (density, 0.66 g/mL).

The mole fraction of pentane in the mixture is 0.38782.

Also, given that from the part (a), the total pressure of the mixture is P_T = 290 torr.

We have to calculate the composition by mole fraction of pentane in the vapor that is in equilibrium with this solution.

Introduction: The formula of the composition by mole fraction in the vapor phase is $y_{i} = \frac{P_{i}^{0} χ_{i}}{P_{T}}$ .

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