Calculate the time complexity for the following function in terms of Big O notation. Explain your answer. [Note: Line numbers are only for reference purpose] int fun (int n) { 1 int count = 0; 2 for (int i = n; i >= 0; i /= 2) 3 count + i; 4 for (int j = 0; j

Calculate the time complexity for the following function in terms of Big O notation. Explain your answer. [Note: Line numbers are only for reference purpose] int fun (int n) { 1 int count = 0; 2 for (int i = n; i >= 0; i /= 2) 3 count + i; 4 for (int j = 0; j

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 8SA

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MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS .
Problem: Recursive Power Method Design a python function that uses recursion to raise a number to a power. The function should accept two arguments: the number to be raised, and the exponent. Assume the exponent is a nonnegative integer. Write the main() function to input the required parameters as shown in thesample input/output. Sample Output:Average number of words per line: 26.0Enter a number: 2Enter a positive whole number between 1 and 100: 102.0 raised to the power of 10 is 1,024.00
Write the definition of a recursive function int simpleSqrt(int n) The function returns the integer square root of n, meaning the biggest integer whose square is less than or equal to n. You may assume that the function is always called with a nonnegative value for n. Use the following algorithm: If n is 0 then return 0. Otherwise, call the function recursively with n-1 as the argument to get a number t. Check whether or not t+1 squared is strictly greater than n. Based on that test, return the correct result. For example, a call to simpleSqrt(8) would recursively call simpleSqrt(7) and get back 2 as the answer. Then we would square (2+1) = 3 to get 9. Since 9 is bigger than 8, we know that 3 is too big, so return 2 in this case. On the other hand a call to simpleSqrt(9) would recursively call simpleSqrt(8) and get back 2 as the answer. Again we would square (2+1) = 3 to get back 9. So 3 is the correct return value in this case.
Question (see uploaded pic): Given Code (Python): def binary_to_decimal_1(str, n): #Base Case/s #Add conditions here for base case/s if True : print("I will be printed before this recursive function ends.") return 0 #Recursive Case/s #Add conditions here for recursive case/s else: return binary_to_decimal_1(str, n) def binary_to_decimal_2(str): #Base Case/s #Add conditions here for base case/s if True : print("I will be printed before this recursive function ends.") return 0 #Recursive Case/s #Add conditions here for recursive case/s else: return binary_to_decimal_2(str) #Handle binary string input. binary_string = input("Please enter a binary string: ")print(binary_string) #Do function calls and print return values.
Question (see uploaded pic): Given Code (Python): def binary_to_decimal_1(str, n): #Base Case/s #Add conditions here for base case/s if True : print("I will be printed before this recursive function ends.") return 0 #Recursive Case/s #Add conditions here for recursive case/s else: return binary_to_decimal_1(str, n) def binary_to_decimal_2(str): #Base Case/s #Add conditions here for base case/s if True : print("I will be printed before this recursive function ends.") return 0 #Recursive Case/s #Add conditions here for recursive case/s else: return binary_to_decimal_2(str) #Handle binary string input. binary_string = input("Please enter a binary string: ")print(binary_string) #Do function calls and print return values.
MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS Use #include<stdio.h> Implement the picture shown below.
2. Consider the following function: def func1(n): output = 1 for i in range (1, n) : output = i return output Rewrite the function as a recursive function.
Python only** Use recursive function* Define countBetween with 2 parameters Use def to define countBetween with 2 parameters thas two parameters: a starting number and an ending number, and counts up (i.e., prints consecutive integers) from the starting number to the ending number. If the numbers are the same, it just prints that number; if the ending number is lower than the starting number, it prints nothing. Do not use any kind of loop Within the definition of countBetween with 2 parameters, do not use any kind of loop. Call countBetween Within the definition of countBetween with 2 parameters, call countBetween in at least one place. Python only** Use recursive function* Define countThereAndBack with 2 parameters Use def to define countThereAndBack with 2 parameters after reaching the ending number, it also counts back down to the starting number. It accepts the same two parameters defining starting and ending numbers it should print nothing if the starting number is…
MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS.
MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS HANDS-ON use #include<stdio.h>
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MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS Use #include<stdio.h> Implement the picture shown below.