Calculate the theoretical yield in grams All; from the complete reaction of 18.3 grams Al according to the following balanced chemical equation: 2 Al(s) + 3 12(s) → 2 All;(s)

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chem101 question. Ignore my work, since it's incorrect. Please explain to me how to set up the equation 

Question 2 of 16
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Calculate the theoretical yield in grams All3 from the complete reaction of 18.3
grams Al according to the following balanced chemical equation:
2 Al(s) +
3 12(s) –
2 All3(s)
1
mol Al
motAT3
407.7
gA
18.3
JAT
26.98
JAT
3
1
mot
STARTING AMOUNT
1 mol Al
2 mol All3
407.7 g All3
18.3 g Al x
= 18.3 g All3
26.98 g Al
3
1 mol All3
ADD FACTOR
DELETE
ANSWER
RESET
*( )
26.98
277
0.678
3
407.7
1.47
18.3
1
2
138
g All3
g/mol Al
g/mol All3
g Al
mol Al
mol All3
+
Transcribed Image Text:Question 2 of 16 Submit Calculate the theoretical yield in grams All3 from the complete reaction of 18.3 grams Al according to the following balanced chemical equation: 2 Al(s) + 3 12(s) – 2 All3(s) 1 mol Al motAT3 407.7 gA 18.3 JAT 26.98 JAT 3 1 mot STARTING AMOUNT 1 mol Al 2 mol All3 407.7 g All3 18.3 g Al x = 18.3 g All3 26.98 g Al 3 1 mol All3 ADD FACTOR DELETE ANSWER RESET *( ) 26.98 277 0.678 3 407.7 1.47 18.3 1 2 138 g All3 g/mol Al g/mol All3 g Al mol Al mol All3 +
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