Calculate the standard enthalpy of formation of the M20(s) metal oxide (AH in kJ/mol) using the following data: Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 124 kJ/mol First ionization energy of M = + 372 kJ/mol Lattice enthalpy of M20(s) = -2115 kJ/mol Refer to the textbook for definitions of ionization energy and electron affinity. Do not use scientific notation for your answer. Do not enter units. Your Answer:

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Calculate the standard enthalpy of formation of the M20(s) metal oxide (AH in
kJ/mol) using the following data:
Bond dissociation enthalpy of O2(g) = +498 kJ/mol
First electron affinity of O = -141 kJ/mol
Second electron affinity of O = +744 kJ/mol
Enthalpy of sublimation of M = + 124 kJ/mol
First ionization energy of M = + 372 kJ/mol
Lattice enthalpy of M20(s) = -2115 kJ/mol
Refer to the textbook for definitions of ionization energy and electron affinity. Do
not use scientific notation for your answer. Do not enter units.
Your Answer:
Answer
Transcribed Image Text:Calculate the standard enthalpy of formation of the M20(s) metal oxide (AH in kJ/mol) using the following data: Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 124 kJ/mol First ionization energy of M = + 372 kJ/mol Lattice enthalpy of M20(s) = -2115 kJ/mol Refer to the textbook for definitions of ionization energy and electron affinity. Do not use scientific notation for your answer. Do not enter units. Your Answer: Answer
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