Calculate the standard enthalpy for the reaction: 4NH3(g) + 502(g) → 4NO(g) + 6H20(g), given the following data: N2(g) + O2(g) → 2NO(g) AHrxn = -43.1 kcal mol-1 N2(g) + 3H2(g) → 2NH3(g) AHrxn = -21.9 kcal mol-1 2H2(g) + O2(g) → 2H2O(g) AHrxn = -115.6 kcal mol-1 %3D

Introductory Chemistry: A Foundation
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Chapter10: Energy
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Problem 80AP: Calculate the enthalpy change when 5.00 g of propane is burned with excess oxygen according to the...
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Calculate the standard enthalpy for the reaction:
4NH3(g) + 502(g) → 4NO(g) + 6H20(g), given the
following data:
N2(g) + O2(g) – 2NO(g)
AHrxn = -43.1 kcal mol-1
%3D
N2(g) + 3H2(g)
2NH3(g)
AHrxn = -21.9 kcal mol-1
2H2(g) + O2(g) →
2H20(g)
AHrxn = -115.6 kcal mol·1
Round your answer to 2 decimal places.
Transcribed Image Text:Calculate the standard enthalpy for the reaction: 4NH3(g) + 502(g) → 4NO(g) + 6H20(g), given the following data: N2(g) + O2(g) – 2NO(g) AHrxn = -43.1 kcal mol-1 %3D N2(g) + 3H2(g) 2NH3(g) AHrxn = -21.9 kcal mol-1 2H2(g) + O2(g) → 2H20(g) AHrxn = -115.6 kcal mol·1 Round your answer to 2 decimal places.
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