Calculate the standard deviation for the molarity of ascorbic acid in the vitamin C supplement solution. What does your standard deviation tell you about the precision of your titration measurements?
Calculate the standard deviation for the molarity of ascorbic acid in the vitamin C supplement solution. What does your standard deviation tell you about the precision of your titration measurements?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the standard deviation for the molarity of ascorbic acid in the vitamin C supplement solution.
What does your standard deviation tell you about the precision of your titration measurements?
Transcribed Image Text:Chemistry 201
College of the Canyons
nart 3. Titration of Unknown Ascorbic Acid Solution with NaOH
Ascorbic Acid Content in Vitamin C Supplements
The neutralization reaction between ascorbic acid and NaOH is:
HC,H,06(aq) + NaOH(aq) NaC,H,06(aq) + H20(1)
Data Table 3. Titration of an Ascorbic Acid Solution
Trial 1
Volume of ascorbic acid
Trial 2
Trial 3
solution, mL
25.00mL
25.00mL
25.00ML
NaOH buret reading
before titration, mL
6.38 mL
10.02 mL
13.94ML
NaOH buret reading
10.02 mL
after titration, mL
13.94 mL
17.76 mL
Volume of NaOH
solution added, mL
3.64 mL
3.92 mL
3.82mL
Mole of NaOH
1.038x 10moi 1.118x10mol 1. 090x 10 mol
Concentration of
0.04152M
0.04472M
0.0436M
ascorbic acid, M
Average ascorbic acid
concentration, M
0.04328 M
(Show work here)
Average concentrahon of Naott = 0,2853M
0.2853 mol NADH
x 0.00364K = 1.038x10 mol NaoH
Trial 1:nE
1.038x103 mol Asconbic acid
= 0.OHI52 M
0,025 L
Trial 2: n= 0.2853 moI NAOH
J.118X10 mol Accorbic acid
x 0.00392L = 1.118x1073
mol NaOH
0.04H12 M
%3D
0.025L
0. 2853 mol NaOH
x0.00382 L= 1.090 x 103
mol NaOH
Trial 3:.2
1.090 x10mol NAOH
10.0436 M
0.025L
64
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