Calculate the sample mean and variance for each treatment and then calculate the t statistic anddegrees of freedom.Kale Biomass (mg)ClayGlass17.537.113.931.131.228.729.937.522.528.1MeanVariance-1)s²2(,– 1)s², + (nz –n +n2 -2t3=d.f. =If you conduct this analysis in R, the output tells you the p-value = 0.042. What conclusion canyou make (i.e., accept or reject the null hypothesis)? Explain how you reached this conclusion.Write a sentence as you would for the results section of a paper.

Answered: Image /qna-images/answer/07fc9cf5-18bd-4a32-b411-58c036e68d5c.jpg

Answered: Calculate the sample mean and variance…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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One of the following is the minimum variance unbiased estimator for u. The sample variance. The sample mean. The sample mean square error. The meadian.
Find the standardized test statistic estimate, z, to test the hypothesis that p, > p,. Use a= 0.01. The sample statistics listed below are from independent samples. Round to three decimal places. Sample statistics: n, = 100, x, = 38, and n2 = 140, X2 = 50 %3D %D O A. 0.638 B. 0.362 O C. 2.116 D. 1.324 S ting Click to select your answer. Type here to search hp 近

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Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
Statistics students believe that the mean score on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 73.5 88 63.9 85.5 62.7 65 83.2 61.9 88 62.7 Test grades are believed to be normally distributed.Use a significance level of 5%. State the alternative hypothesis: HA:HA: μ>65μ>65 μ<65μ<65 μ≠65μ≠65 State the mean of the sample: State the standard error of the sample means: State the test statistic: t=t= State the p-value: Decision: Fail to reject the null hypothesis. Reject the null hypothesis.
Use the following sample to evaluate H0: μ = 65, at significance level α = 0.05. 53 75 68 53 57 12 4 10 45 94 23 73 9 41 79 92 90 46 49 71 State the correct test and your conclusion. T-test. Reject Ho. T-test. Fail to reject Ho. Z-test. Fail to reject Ho. Z-test. Reject Ho.
The following table shows the results of an analysis of variance comparing three treatment conditions. What is the value of h2, the percentage of variance accounted for? Source SS df MS Between 30 2 15 F = 7.50 Within 60 30 2 Total 90 32
3.Which model do you think is the “best” reduced model? Discuss why you choose this model. Analysis of Variance Table (Step back model) Response: rent Df Sum Sq Mean Sq F value Pr(>F) age 1 21000 21000 17.1136 0.0003079 *** sqft 1 35364 35364 28.8196 1.134e-05 *** sd 1 5961 5961 4.8576 0.0362339 * unts 1 8678 8678 7.0722 0.0130049 * gar 1 33364 33364 27.1899 1.713e-05 *** cp 1 7641 7641 6.2269 0.0189934 * Residuals 27 33131 1227 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 Step forward model: Response: rent Df Sum Sq Mean Sq F value Pr(>F) age 1 21000 21000 16.6255 0.000406 *** sqft 1 35364 35364 27.9976 1.757e-05 *** sd 1 5961 5961 4.7191 0.039517 * unts 1 8678 8678 6.8705 0.014697 * gar 1 33364 33364 26.4144 2.599e-05 *** cp 1 7641 7641 6.0493 0.021176 *…
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
Listed below are time intervals (min) between eruptions of a geyser. The "recent" times are within the past few years, and the "past" times are from 1995. Does it appear that the variation of the times between eruptions has changed? Use a 0.05 significance level. Assume that the two populations are normally distributed. E Click the icon to view the sample data. - X Sample data Identify the test statistic. The test statistic is (Round to two decimal places as needed.) Identify the P-value Recent 79 95 89 75 55 97 66 90 66 86 81 87 Past 92 85 94 99 68 82 89 98 84 98 92 91 The P-value is (Round to three decimal places as needed.) Print Done What is the conclusion for this hypothesis test? O A. Reject Ho. There is sufficient evidence to support the claim that the variation of the times between eruptions has changed. O B. Reject Ho. There is insufficient evidence to support the claim that the variation of the times between eruptions has changed. OC. Fail to reject Hg. There is sufficient…

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