Calculate the reaction forces on the bearing near the pulley and bearing at the far end of the shaft. Include a free body diagram and coordinates. Given the shaft length is 1 meter= Mass=40Kg Static load = 8600N Dynamic (running load) = 8400N Some hints: 1. This solution will require you to draw known forces and find unknown reactions in 2 perpendicular planes and then add the horizontal and vertical reaction forces as vectors to find the reaction force (hypotenuse). 2. Bearings are usually mounted as near as possible to the ends of the shaft without fouling the other machine elements. The bearing at the far shaft end can be mounted at the 1 meter point. The bearing at the pulley end should allow clearance to assemble the pulley. 3. Bearing reaction forces are typically simplified as a single point load through the bearing centre.
Calculate the reaction forces on the bearing near the pulley and bearing at the far end of the shaft. Include a free body diagram and coordinates. Given the shaft length is 1 meter= Mass=40Kg Static load = 8600N Dynamic (running load) = 8400N Some hints: 1. This solution will require you to draw known forces and find unknown reactions in 2 perpendicular planes and then add the horizontal and vertical reaction forces as vectors to find the reaction force (hypotenuse). 2. Bearings are usually mounted as near as possible to the ends of the shaft without fouling the other machine elements. The bearing at the far shaft end can be mounted at the 1 meter point. The bearing at the pulley end should allow clearance to assemble the pulley. 3. Bearing reaction forces are typically simplified as a single point load through the bearing centre.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Calculate the reaction forces on the bearing near the pulley and bearing at the far end of the shaft. Include a free body diagram and coordinates.
- Given the shaft length is 1 meter=
- Mass=40Kg
- Static load = 8600N
- Dynamic (running load) = 8400N
Some hints:
1. This solution will require you to draw known forces and find unknown reactions in 2
perpendicular planes and then add the horizontal and vertical reaction forces as
vectors to find the reaction force (hypotenuse).
2. Bearings are usually mounted as near as possible to the ends of the shaft without
fouling the other machine elements. The bearing at the far shaft end can be mounted
at the 1 meter point. The bearing at the pulley end should allow clearance to assemble
the pulley.
3. Bearing reaction forces are typically simplified as a single point load through the
bearing centre.
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