**Calculating the pK at 25°C for a Chemical Reaction**To calculate the pK of a reaction at 25 degrees Celsius, we use the provided thermodynamic data. The gas constant \( R \) is given as 8.314 J/mol/K.### Reaction:\[ 1\text{A} + 1\text{B} + 2\text{C} \rightarrow 1\text{D} + 5\text{E} \]### Thermodynamic Data:| Compound | \( \Delta H_f^0 \) (kJ/mol) | \( S^0 \) (J/mol/K) ||----------|----------------------------|---------------------|| A | 8.65 | 13.50 || B | 3.22 | 13.55 || C | 1.04 | 0.97 || D | -1.02 | 8.37 || E | 16.36 | 15.55 |### Answer:The initial calculation gave an incorrect pK value of -2.97. The corrected value is (8.73).

Calculate the pK at 25 degrees C of the following reaction using the data in the table. Use R = 8.314 J/mol/K. 1A +1B + 2C AHf (kJ/mol) A 8.65 B 3.22 C 1.04 D -1.02 E 16.36 Answer: -2.97 × (8.73) 1D + 5E so(J/mol/K) 13.50 13.55 0.97 8.37 15.55

Calculate the pK at 25 degrees C of the following reaction using the data in the table. Use R = 8.314 J/mol/K. 1A +1B + 2C AHf (kJ/mol) A 8.65 B 3.22 C 1.04 D -1.02 E 16.36 Answer: -2.97 × (8.73) 1D + 5E so(J/mol/K) 13.50 13.55 0.97 8.37 15.55

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Chemistry
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